Cost per meter(C) = $60/m
Length of rectangular field(L) = 50m
L = 2W
-> W = L/2
-> W = 50/2
-> Width of rectangular field = 25m
Cost of one field length(l) = L x C
-> l = 50 x 60
-> l = $3000
Two of the lengths of the field = 2 x l
-> 2 x $3000
-> $6000
Cost of one field width(w) = W x C
-> w = 25 x 60
-> w = $1500
Two of the widths of the field = 2 x w
-> 2 x $1500
-> $3000
Cost of fencing entire field = $6000+$3000
Hence, total field cost = $9000
The correct matches are as follows:
quartile
10.5
<span>median
41
third quartile
</span>38.5<span>
the difference of the largest value and the median
49-41 = 8
Hope this answers the question. Have a nice day. Feel free to ask more question.
</span>
I can't read that language but I'll guess it says write a second degree equation then solve for n when d=10.
Answer: n² - 3n - 20 = 0
That doesn't factor so there is no integer n solution.
That means there are no polygons with 10 diagonals.
Answer:
$30 i think
Step-by-step explanation:
because %40+%10=%50
and %50 is half of %100 so 60-(60×(50%)=30
sorry is its wrong
Diagonals of a parallelogram bisect each other. It is not relevant that PN=9. since AO=4 then AM=4
