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pantera1 [17]
3 years ago
13

A graph in the form y = ax2 will have a vertex at __

Mathematics
2 answers:
alex41 [277]3 years ago
6 0

Answer: For a given quadratic y = ax2 + bx + c, the vertex (h, k)

Step-by-step explanation:

pychu [463]3 years ago
3 0

A graph in the form y = ax2 will have a vertex at h, k.

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the cheerleading squad made 4 5/8 gallon of lemonade to sell at the basketball game. they sold 2 7/8 gallons. how many gallons w
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4 5/8 = 37/8
2 7/8= 23/8
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This rectangle has side lengths r and s.
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2 years ago
Advertising expenses are a significant component of the cost of goods sold. Listed below is a frequency distribution showing the
Alexxandr [17]

Answer:

Step-by-step explanation:

The table can be computed as:

Advertising Expenses ($ million)     Number of companies

25 up to 35                                                    4

35 up to 45                                                    19

45 up to 55                                                    27

55 up to 65                                                    16

65 up to 75                                                     9

TOTAL                                                            75

Let's find the probabilities first:

P(25 - 35) = P \Big(\dfrac{25-50.93}{10.80}

For 35 up to 45

P(35 - 45) = P \Big(\dfrac{35-50.93}{10.80}

For 45 up to 55

P(45 - 55) = P \Big(\dfrac{45-50.93}{10.80}

For 55 up to 65

P(55 - 65) = P \Big(\dfrac{55-50.93}{10.80}

For 65 up to 75

P(65 - 75) = P \Big(\dfrac{65-50.93}{10.80}

Chi-Square Table can be computed as follows:

Expense   No of   Probabilities(P)  Expe                (O-E)^2   \dfrac{(O-E)^2}{E}

             compa                                 cted E (n*p)

             nies (O)  

25-35           4      0.0612    75*0.0612 = 4.59        0.3481       0.0758

35-45           19     0.2218   75*0.2218 = 16.635     5.5932       0.3362

45-55           27     0.3568   75*0.3568 = 26.76     0.0576      0.021

55-65           16      0.2552   75*0.2552 = 19.14      9.8596      0.5151

65-75           9      0.0839     75*0.0839 = 6.2925   7.331         1.1650

                                                                                           \sum \dfrac{(O-E)^2}{E}= 2.0492                                                                                                      

Using the Chi-square formula:

X^2 = \dfrac{(O-E)^2}{E} \\ \\ Chi-square  \ X^2 = 2.0942

Null hypothesis:

H_o: \text{The population of advertising expenses follows a normal distribution}

Alternative hypothesis:  

H_a: \text{The population of advertising expenses does not follows a normal distribution}

Assume that:

\alpha = 0.02

degree of freedom:

= n-1

= 5 -1

= 4

Critical value from X^2 = 11.667

Decision rule: To reject H_o  \  if \  X^2  test statistics is greater than X^2 tabulated.

Conclusion: Since X^2 = 2.0942 is less than critical value 11.667. Then we fail to reject H_o

6 0
3 years ago
Can anyone please help me please
Rashid [163]

Answer:

this isnt spanish

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Work at a convenience store 60% of your time, and earn $11.00 an hour. Referee games at your city park 25% of your time, and ear
pogonyaev

Answer:

13.75

Step-by-step explanation:

The expected value of the hourly wage is the sum of the probabilities (percentage of time spent on each job) multiplied by the payoff (money earned) from each possible occurrence (job):

(0.6 × 11) + (0.25 × 19) + (0.15 × 16) = $13.75.

3 0
3 years ago
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