Question

What is the value of w in the solution to the following system of linear equations?

Answer 1

Answer:

>>>>w = - 1 / 6<<<<

Answer 2

For this case we have a system of two linear equations with two igcognitas, given by:

$5v + 4w = 1\\3v-6w = 2$

Where v and w are the unknowable variables.

To solve, we perform the following steps:

1st step:

We multiply the first equation by 3:

$15v + 12w = 3$

2nd step:

We multiply the second equation by -5:

$-15v + 30w = -10$

3rd step:

We add the equations:

$15v + 12w = 3\\-15v + 30w = -10$

We have then:

$42w = -7$

$w =-\frac{7}{42}$

$w =-\frac{1}{6}$

Thus, the value of w is $-\frac{1}{6}$.

4th step:

We substitute $w =-\frac{1}{6}$ in any of the equations:

$3v-6w = 2\\3v-6 * (-\frac{1}{6}) = 2$

$3v + 1 = 2\\3v = 2-1\\3v = 1$

$v =\frac{1}{3}$

So, the value of v is $\frac{1}{3}$

Answer:

The value of w is $-\frac{1}{6}$