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disa [49]
3 years ago
6

How can you use the Pythagorean Theorem to solve real-world problems?

Mathematics
1 answer:
Tju [1.3M]3 years ago
7 0
1st answer is lengths and 2nd answer is right triangles
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12.5 of what number is 150
Y_Kistochka [10]

Answer: 1,200


Step-by-step explanation:

1,200 x .125 = 150


4 0
3 years ago
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the ratio of dogs to cats is 5:3 ,the ratio of fish to dogs is 6:1 .what is the ratio of cats to fish
e-lub [12.9K]

Answer:

10: 1

Step-by-step explanation:

We have to make the dogs art of the ratio equal first.

5:3>30:18

6:1> 180: 30

After this we have to simplify the ratio.

Cats to fish is 180:18 (divide by 2) 90:9 (then by 3) 30 : 3 (and finally by 3 again) 10 : 1

4 0
2 years ago
Solve the equation <br> 0.5 (14a + 46) = -11a - 42 + 5a
Nata [24]

Answer:

a = - 5

Step-by-step explanation:

Given

0.5(14a + 46) = - 11a - 42 + 5a ← distribute left side

7a + 23 = - 6a - 42 ( add 6a to both sides )

13a + 23 = - 42 ( subtract 23 from both sides )

13a = - 65 ( divide both sides by 13 )

a = - 5

7 0
3 years ago
Read 2 more answers
The probability that a random student at Elmville College is a freshman is 0.3; a sophomore, 0.25; and a junior or senior, 0.45.
Andre45 [30]
Let L_1 denote the event that a student is a freshman, L_2 a sophomore, L_3 a junior, and L_4 a senior.

Let E denote the event that a student majors in engineering. By the law of total probability,

\mathbb P(E)=\mathbb P(E\cap L_1)+\mathbb P(E\cap L_2)+\mathbb P(E\cap L_3)+\mathbb P(E\cap L_4)

By the definition of conditional probability, we can expand each of these intersection probabilities to get

\mathbb P(E)=\mathbb P(E\mid L_1)\mathbb P(L_1)+\mathbb P(E\mid L_2)\mathbb P(L_2)+\mathbb P(E\mid L_3)\mathbb P(L_3)+\mathbb P(E\mid L_4)\mathbb P(L_4)

\mathbb P(E)=0.15\cdot0.3+0.2\cdot0.25+2(0.3\cdot0.45)=0.365
8 0
3 years ago
Law of cosines: a2 = b2 + c2 – 2bccos(A) Find the measure of Q, the smallest angle in a triangle whose sides have lengths 4, 5,
Ierofanga [76]
We are tasked to solve for the smallest angle using the law of cosines given that the three sides of the triangle are 4,5 and 6.
a=4 , b=5, c=6
Angle 1:
cosA = 5² + 6² - 4² / 2*5*6
A=41.41°

Angle 2:
cos B = 4²+6² -5² /2*4*6
B= 55.77°

Angle C:
C = 180° - 41.41° - 55.77°
C = 82.82°

The smallest angle is A which is equal to 41.41°.
4 0
3 years ago
Read 2 more answers
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