What expression is equivalent to 24b-34ab

Which best describes the dimensions of a plane?

n200080 [17]

Answer: C) 2 dimensions; flat surface of length and width, but no depth

One way to think of a plane is to think of a flat sheet of paper that extends infinitely in all directions. The paper must be kept flat without any bends.

6 0

3 years ago

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1) Graph the following lines and using the graph determine several values of x for which the graph is positive (negative):

Aleksandr [31]

1) $y=-0.5x-2$

The graph of the above equation is attached in the attachment below.

For all the values from negative infinity to -4, the function is positive.

X ∈ (-∞,-4]

2) $y=-1.5x+3$

To find the x- intercept, plug y =0

$0=-1.5x+3$

$1.5x=3$

$x=2$

x intercept = (2,0)

To find the y- intercept, plug x=0

$y=-1.5(0)+3$

$y=3$

Y- intercept = ( 0,3)

3) $y=13-x$

Y- intercept = (0,13)

x- intercept = (13,0)

Area of triangle = $\frac{bh}{2}$

Area of triangle = $\frac{13\times13}{2}$

Area = $\frac{169}{2}$ sq unit.

4) The graphs of $y=-2x+7$ and $y=0.5x-5.5$ is attached in the attachment below.

The intersection point is ( 5,-3)

5) A = (-3,0)

B = (4,5)

C = (0,-4)

Slope of AB = $\frac{5-0)}{4-(-3)} =\frac{5}{7}$

Slope intercept of line $y=mx+b$

Where, m is the slope and b is the y- intercept.

Plugging point A and the slope in the y- intercept to find the value of b.

$0=\frac{5(-3)}{7} +b$

$b=\frac{15}{7}$

Equation of line AB: $y=\frac{5x}{7} +\frac{15}{7}$

Slope of BC = $\frac{-4-5}{0-4} =\frac{9}{4}$

Plug C = (0,-4)

$-4=0+b$

b=-4

equation of line BC= $y=\frac{9x}{4} -4$

Slope of line AC = $\frac{-4-0}{0--3} =\frac{-4}{3}$

Equation of line AC = $y=\frac{-4x}{3} -4$

Y intercept of AB = $(0,\frac{15}{7} )$

5 0

4 years ago

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Question 4 of 10, Step 1 of 1 1/out of 10 Correct Certify Completion Icon Tries remaining:0 The Magazine Mass Marketing Company

erastovalidia [21]

Answer:

0.0105 = 1.05% probability that no more than 3 of the entry forms will include an order.

Step-by-step explanation:

For each entry form, there are only two possible outcomes. Either it includes an order, or it does not. The probability of an entry including an order is independent of any other entry, which means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

The Magazine Mass Marketing Company has received 16 entries in its latest sweepstakes.

This means that $n = 16$

They know that the probability of receiving a magazine subscription order with an entry form is 0.5.

This means that $p = 0.5$

What is the probability that no more than 3 of the entry forms will include an order?

At most 3 including an order, which is:

$P(X \leq 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3)$

In which

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{16,0}.(0.5)^{0}.(0.5)^{16} \approx 0$

$P(X = 1) = C_{16,1}.(0.5)^{1}.(0.5)^{15} = 0.0002$

$P(X = 2) = C_{16,2}.(0.5)^{2}.(0.5)^{14} = 0.0018$

$P(X = 3) = C_{16,3}.(0.5)^{3}.(0.5)^{13} = 0.0085$

Then

$P(X \leq 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) = 0 + 0.0002 + 0.0018 + 0.0085 = 0.0105$

0.0105 = 1.05% probability that no more than 3 of the entry forms will include an order.

6 0

3 years ago

Assume the annual interest rate is 6%. Calculate the value of an investment that pays $100 every two years, starting two

olganol [36]

Answer:

all me know is u make lot of dollar

Step-by-step explanation:

me biiiiiigggg brain

8 0

3 years ago

A cookie company packages its cookies in rectangular prism boxes designed with square bases that have both a length and width of

Verdich [7]

Answer:

length and width=4

height=8

Step-by-step explanation:

Hello to solve this problem we must propose a system of equations of 3x3, that is to say 3 variables and 3 equations.

Ecuation 1

Leght=Width

.L=W

Ecuation 2

To raise the second equation we consider that the length and width of 4 inches less than the height of the box

H-4=W

Ecuation 3

To establish equation number 3, we find the volume of a prism that is the result of multiplying length, width, and height

LxWxH=128

From ecuation 1(w=h)

$HW^2=128$

solving for H

$H=\frac{128}{W^2}$

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<em>Using ecuation 2</em>

H-4=W

$\frac{128}{W^2}-4=W\\W^3+4W^2-128=0$

Now we find the roots of the equation, 2 of them are imaginary, and only one results in 4

W=4in

L=4in

to find the height we use the ecuation 2

H-4=W

H=4+W

H=4+4=8

H=8IN

7 0

3 years ago