Answer: a - 4.512 hours
b - 1.94 hours
Step-by-step explanation:
Given,
a) A(t) = 10 (0.7)^t
To determine when 2mg is left in the body
We would have,
A(t) = 2, therefore
2 = 10(0.7)^t
0.7^t =2÷10
0.7^t = 0.2
Take the log of both sides,
Log (0.7)^t = log 0.2
t log 0.7 = log 0.2
t = log 0.2/ 0.7
t = 4.512 hours
Thus it will take 4.512 hours for 2mg to be left in the body.
b) Half life
Let A(t) = 1/2 A(0)
Thus,
1/2 A(0) = A(0)0.7^t
Divide both sides by A(0)
1/2 = 0.7^t
0.7^t = 0.5
Take log of both sides
Log 0.7^t = log 0.5
t log 0.7 = log 0.5
t = log 0.5/log 0.7
t = 1.94 hours
Therefore, the half life of the drug is 1.94 hours
Can you tell me what you need help because it doesn't says
Which expression has the same value as the one below?
i dont kown cause i cant see the choices
Answer:
The answer is 22 1/2-18 3/7. first we need to get a common denominator for the fractions. I will do 14. Now we have 22 7/14-18 6/14=4 1/14 ez
Step-by-step explanation:
Answer:
y = 2x - 1
Step-by-step explanation:
Slope = (5-1) / (3-1) = 4/2 = 2
y-intercept = 1 - (2)(1) = - 1
y = 2x - 1