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Delvig [45]
2 years ago
6

Which expression has the same value as the one below?

Mathematics
1 answer:
9966 [12]2 years ago
7 0

Which expression has the same value as the one below?

i dont kown cause i cant see the choices

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URGENT NEED IMMEDIATE SUPPORT WILLING TO GIVE BRAINLY
frozen [14]

4 hours for 18

7 hours for 25.50

Difference in hours: 7-4 = 3

Difference in cost: 25.50 - 18 = 7.50

7.50 / 3 = 2.50

A. They charge 2.50 per hour.

B. 2.50 x 4 = 10

18 - 10 = 8

The flat fee is 8 dollars

C. 8 + (2 x 2.50) = 13 dollars

8 0
2 years ago
Help me pleaseee please
Karolina [17]

Answer:

1) c/d = pi

Step-by-step explanation:

since c= pi x d

divide both sides by d

c/d = pi

5 0
2 years ago
Which expressions are equivalent to 4m + 12? Choose ALL that apply.<br>​
riadik2000 [5.3K]

Answer:

Step-by-step explanation:

Option 1:

4(m + 12) = 4m + 48 (not what we want)

Option 2:

6m - 2m + 12 = 4m + 12 (one of the right answers)

Option 3:

4(m + 3) = 4m + 12 (one of the right answers)

Option 4:

3m - m + 12 = 2m + 12 (not what we want)

Therefore the correct answers are Option 2 and Option 3.

6 0
2 years ago
Read 2 more answers
* Let S = Span {(2,-1, 1), (3, 1, 1), (1, 2, 0)}. (i) Calculate the dimension of S.
Sholpan [36]

The span of 3 vectors can have dimension at most 3, so 9 is certainly not correct.

Check whether the 3 vectors are linearly independent. If they are not, then there is some choice of scalars c_1,c_2,c_3 (not all zero) such that

c_1 (2,-1,1) + c_2 (3,1,1) + c_3 (1,2,0) = (0,0,0)

which leads to the system of linear equations,

\begin{cases} 2c_1 + 3c_2 + c_3 = 0 \\ -c_1 + c_2 + 2c_3 = 0 \\ c_1 + c_2 = 0 \end{cases}

From the third equation, we have c_1=-c_2, and substituting this into the second equation gives

-c_1 + c_2 + 2c_3 = 2c_2 + 2c_3 = 0 \implies c_2 + c_3 = 0 \implies c_2 = -c_3

and in turn, c_1=c_3. Substituting these into the first equation gives

2c_1 + 3c_2 + c_3 = 2c_3 - 3c_3 + c_3 = 0 \implies 0=0

which tells us that any value of c_3 will work. If c_3 = t, then c_1=t and c_2 = -t. Therefore the 3 vectors are not linearly independent, so their span cannot have dimension 3.

Repeating the calculations above while taking only 2 of the given vectors at a time, we see that they are pairwise linearly independent, so the span of each pair has dimension 2. This means the span of all 3 vectors taken at once must be 2.

3 0
1 year ago
Help plsss I’m a little confused<br> We started this today :/
belka [17]
We can’t see the question
3 0
2 years ago
Read 2 more answers
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