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elena-s [515]
3 years ago
8

Two sides of a triangle measure 2x – 4 and 7x – 2 units, respectively. Which of these is a possible length for the third side of

the triangle?
A 3X
B 6X
C 5X+2
D 9X-6
Mathematics
2 answers:
Fynjy0 [20]3 years ago
3 0

Answer:

<h3>B. 6x.</h3>

Step-by-step explanation:

Given two sides of a triangle 2x – 4 and 7x – 2 units.

<em>Difference of two sides of a triangle is less than third side.</em>

Let us find the difference of 7x – 2 and 2x – 4, we get

7x-2 - (2x-4) = 7x -2 -2x +4

= 5x + 2.

Third side should be less then 5x+2, so 5x+2 can't be third side.

<em>Sum of two sides is greater than third side.</em>

Adding given sides of triangle, we get

7x-2 +2x-4 = 9x - 6.

Third side should be greater than 9x-6. So, 9x-6 can't be third side.

Now, if we add 3x and 2x-4, we get

3x+2x-4 = 5x-4, which is less than 9x - 6.

So, 3x can't be third side.

Therefore, correct option is :

<h3>B. 6x</h3>
Andrews [41]3 years ago
3 0

The lengths of the sides of a triangle must all be a positive number of units. For this reason, since 2x – 4 and 7x – 2 must both be positive, x must be greater than 2, and when x is greater than 2, 7x – 2 is always greater than 2x – 4. Thus, the third side of the triangle must be less than (7x – 2) + (2x – 4) units long and greater than (7x – 2) – (2x – 4) units long. In other words, it must be less than 9x – 6 units long and greater than 5x + 2 units long. Therefore, a possible length for the third side of the triangle is 6x units.

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(-10)³ * 3 * 2 * (-7 ) <br> Please help
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Answer:

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Step-by-step explanation:

8 0
2 years ago
What is the slope of a line that is perpendicular to the line<br> y = 2x – 6?
Zolol [24]

Answer:

The slope of a line that is perpendicular to the line y = 2x – 6 is -1/2.

Step-by-step explanation:

The slope-intercept form of the line equation

y = mx+b

where

  • m is the slope
  • b is the y-intercept

Step 1:

Finding the slope of the given equation

The given equation is

y = 2x - 6

comparing with the slope-intercept form of the line equation

The slope of the equation is: m = 2

Step 2:

Determining the slope of the perpendicular line

In Mathematics, a line perpendicular to another line has a slope that is the negative reciprocal of the slope of the other line.

  • As the slope of the equation is: m = 2

Therefore, the slope of the new perpendicular line:

-\frac{1}{m}=-\frac{1}{2}

Hence, the slope of a line that is perpendicular to the line y = 2x – 6 is -1/2.

Important Tip:

  • The product of the slopes of perpendicular lines is -1.

<u>Verification:</u>

The slope of the given line:

m_1=2

The slope of the perpendicular line:

m_2=-\frac{1}{2}\:\:\:\:

The product of the slopes is:

\:m_1\times \:m_2\:=2\times -\frac{1}{2}\:\:=-1

As the product of the slopes of perpendicular lines is -1, therefore, the lines are perpendicular.

Thus, the slope of a line that is perpendicular to the line y = 2x – 6 is -1/2.

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How do you do a, b, c, d? With work shown thank you.
BigorU [14]

I will do a and b and you do the rest.


For (a), the equation is x + y = 154.


For (b), the equation is 320x + 85y = 14,970.


We have two equations in two unknowns.


Use the substitute method to find x and y (the given c). Once you have x and y, use that to find d.


Take it from here.


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3 years ago
What is the value of a1 for a geometric sequence with a4=40 and a6=160?
Elenna [48]

Answer:

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Step-by-step explanation:

The nth term of a geometric series is:

a_n = a₁ (r)^(n-1)

where a₁ is the first term and r is the common ratio.

Here, we have:

40 = a₁ (r)^(4-1)

160 = a₁ (r)^(6-1)

40 = a₁ (r)^3

160 = a₁ (r)^5

If we divide the two equations:

4 = r^2

r = 2

Now substitute into either equation to find a₁:

40 = a₁ (2)^3

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