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ch4aika [34]
4 years ago
13

If 75% of the students in today's grade voted,how many students are in toby's grade

Mathematics
2 answers:
LenKa [72]4 years ago
8 0
100% because its 100%
Nimfa-mama [501]4 years ago
6 0

There are 200 students in Toby's grade

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What is this? Please help
larisa [96]

Answer:

y=-34

Step-by-step explanation:

-51÷3=-17

-17×2=-34

Please mark me brainliest and thank me

5 0
3 years ago
Which is the solution to the system of equations? y=−3/2x−11/2; 6x+y=−4
cupoosta [38]

Answer:

x= 1/3  and y=−6

Step-by-step explanation:

If you want step by step explanation you can get your explanation from

https://www.mathpapa.com And just type that answer in where it says what do you want to  calculate? type it in that box and it give you step by step but i gave you the answer up top you just need the explanation the explanation is hard to type in here that's why i have you that website :)

4 0
3 years ago
The length of a rectangle is 3 cm less than twice the width. If the perimeter is 42 cm, what is the length of the rectangle?
larisa [96]

Answer:

The length is 13

Step-by-step explanation:

w+w+l+l= perimeter

if the length is 3m less than twice the width then let's do some math.

42 divided 2 =21. so the width and length of one side have to equal 21. For example, let's use 8 as the width. The length would be twice(16) minus three(13) 13 plus 8 is 21. WOW it equals half of it so no we know the length is 13 and the wdith is 8.

6 0
3 years ago
8. A square has side length 6 inches. A parallelogram has a base of 6 inches,
wlad13 [49]

Answer:

The height is 6 inches.

Step-by-step explanation:

Area of the square = length of a side squared.

This square has area 6^2 = 36 in^2.

Area of the parallelogram =  base * height

= 6h.

As the areas are equal:

6h = 36

h = 36/6 = 6 inches.

6 0
3 years ago
T F IfA and B are similar matrices, then AT=BT
muminat

Answer:

Step-by-step explanation:

We know that for two similar matrices A and B exists an invertible matrix P for which

[tex]B = P^{-1} AP[/tex]

∴ B^{T} = (P^{-1})^{T} A^{T} P^{T} \\

Also P^{-1}P = I\\

and (P^{-1})^{T} = (P^{T})^{-1}

∴(P^{-1})^{T}P^{T} = I

so, B^{T} = (P^{-1})^{T} A^{T} P^{T} = (P^{T})^{-1}A^{T} P^{T}\\B^{T} = A^{T} I\\B^{T} = A^{T}

7 0
3 years ago
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