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Nutka1998 [239]
3 years ago
10

Marta's jump rope is 10" shorter than four times the length of Dilbert's rope. If both their ropes laid together end to end and

measured 120" long, how long is Marta's rope?
Mathematics
1 answer:
sladkih [1.3K]3 years ago
3 0

Answer:

Marta's rope is 94"

Step-by-step explanation:

D = dilberts rope length

M = marta's rope length

Marta's jump rope is 10" shorter than four times the length of Dilbert's rope

M = 4D-10

both their ropes laid together end to end and measured 120" long

M+D = 120

Substitute 4D-10 for M in the second equation

4D-10 + D = 120

Combine like terms

5D-10=120

Add 10 to each side

5D-10+10 =120+10

5D =130

Divide by 5

5D/5 = 130/5

D =26

Now we need to find M

M+D = 120

M +26 = 120

Subtract 26 from each side

M = 120-26

M = 94

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Answer:

The correct options are 1, 2 and 4.

Step-by-step explanation:

The given triangle is an equilateral triangle. All the sides of an equilateral triangle are same. All interior angles are equal with measure 60 degree.

The distance from the center of an equilateral triangle to the midpoint of a side is known as apothem. In the given figure letter a represents the apothem.

Point D is the midpoint of BC,

b=\frac{BC}{2}=\frac{8.7}{2}=4.35

Use Pythagorean theorem in triangle COD. So, option 1 is correct.

OC^2=OD^2+DC^2

5^2=a^2+(4.35)^2

25=a^2+18.9225

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a\approx\pm 2.5

The distance can not be negative, so the length of the apothem is approximately 2.5 cm. Option 4 is correct.

The line OC bisects the angle C.

tan(30^{\circ})=\frac{a}{b}

\frac{1}{\sqrt{3}=\frac{a}{4.35}

a\approx\pm 2.5

Therefore option 2 is correct.

The perimeter of an equality triangle is

P=3a=3(8.7)=26.1

Option 3 is incorrect.

A=\frac{\sqrt{3}}{4}a^2=\frac{\sqrt{3}}{4}(8.7)^2=32.77

Option 5 is incorrect.

Therefore options 1, 2 and 4 are correct.

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