Split
into two component segments,
and
, parameterized by


respectively, with
, where
.
We have


where 
so the line integral becomes



Answer:
21
Step-by-step explanation:
Because h(3) times h(7) is equal to 21.
Hope it helps!
Answer:
GG JUJUYTBNHYJKY7UJN HGJNGHGJBTRYDYJYHBGHTDFGBGF
Step-by-step explanation:
The answer is: gof = 1, 1, and 2
Answer:
_____ is used to find a certain information from the list?Cell address used in formula is also called as _____?