Ask question

Ask question

All categories

3 years ago

12

Please help this is hard

2 answers:

Ket [755]3 years ago

6 0

The sides that are congruent are sides AB and side DC

morpeh [17]3 years ago

5 0

Hi!

Parallelograms have 4 sides. The parallel lines have equal lengths.

Which means sides BC, and AD are equal. <span>AB, DC</span> are also equal.

Only AB, DC are listed as an option so the answer is Sides AB and DC.

Hope this helps! :)
-Peredhel

You might be interested in

Given two functions f(x)=2x+4 and g(x)=−1/5x−3 , what is the function rule for (f+g)(x) ?

Angelina_Jolie [31]

The definition is pretty simple:

$(f+g)(x) = f(x)+g(x)$

So, we only have to sum the expressions:

$f(x)+g(x) = 2x+4 - \dfrac{1}{5}x-3 = \dfrac{9}{5}x+1$

5 0

3 years ago

Select the number line model that matches the expression 1/4 - 5/4

Yuri [45]

Answer:

The answer would be -5/4

3 0

3 years ago

A rectangular prism has dimensions of 4 cm by 3 cm by 2 cm.

EastWind [94]

Answer:

HN

Step-by-step explanation:

6 0

3 years ago

23q−34) and (−16q−r)

faltersainse [42]

Answer:

r = 7 q - 34

Step-by-step explanation:

Solve for r:

-34 + 7 q - r = 0

Subtract 7 q - 34 from both sides:

-r = 34 - 7 q

Multiply both sides by -1:

Answer: r = 7 q - 34

7 0

4 years ago

Read 2 more answers

Find all solutions of the equation algebraically. Use a graphing utility to verify the solutions graphically. (Enter your answer

Anuta_ua [19.1K]

Answer:

The solutions of the equation are 0 and 0.75.

Step-by-step explanation:

Given : Equation $16x^4 - 24x^3 +9x^2 =0$

To find : All solutions of the equation algebraically. Use a graphing utility to verify the solutions graphically ?

Solution :

Equation $16x^4 - 24x^3 +9x^2 =0$

$x^2(16x^2-24x+9)=0$

Either $x^2=0$ or $16x^2-24x+9=0$

When $x^2=0$

$x=0$

When $16x^2-24x+9=0$

Solve by quadratic formula, $x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

$x=\frac{-(-24)\pm\sqrt{(-24)^2-4(16)(9)}}{2(16)}$

$x=\frac{24\pm\sqrt{0}}{32}$

$x=\frac{24}{32}$

$x=\frac{3}{4}$

$x=0.75$

The solutions of the equation are 0 and 0.75.

For verification,

In the graph where the curve cut x-axis is the solution of the equation.

Refer the attached figure below.

7 0

3 years ago