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NARA [144]
2 years ago
12

Please help this is hard

Mathematics
2 answers:
Ket [755]2 years ago
6 0
The sides that are congruent are sides AB and side DC
morpeh [17]2 years ago
5 0
Hi!

Parallelograms have 4 sides. The parallel lines have equal lengths. 

Which means sides BC, and AD are equal. <span>AB, DC</span> are also equal. 

Only AB, DC are listed as an option so the answer is Sides AB and DC.

Hope this helps! :)
-Peredhel
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The rectangular diagram shows the design for a tood
Ksivusya [100]

Answer:

Step-by-step explanation:

What diagram?

8 0
3 years ago
Convert to an improper fraction. Type in your answer with the negative in the numerator.
MariettaO [177]

Answer:

-35/4

Step-by-step explanation:

6 0
3 years ago
Select the correct answer.
Serjik [45]

Answer:

A . (2,4)

Step-by-step explanation:

Let's solve for x.

x+2y≤4

Step 1: Add -2y to both sides.

x+2y+−2y≤4+−2y

x≤−2y+4

Answer:

x≤−<u>2</u>y+<u>4</u>

5 0
3 years ago
Find the area of the following ellipse (round to nearest tenth).
goblinko [34]

Answer:

\huge\boxed{A=60\pi cm^2}

Step-by-step explanation:

The formula of an area of a elipse:

A=\pi ab

We have:

2a=10cm\to a=5cm\\\\2b=24cm\to b=12cm

Substitute:

A=\pi\dot5\cdot12=60\pi(cm^2)

8 0
2 years ago
National data indicates that​ 35% of households own a desktop computer. In a random sample of 570​ households, 40% owned a deskt
Elan Coil [88]

Answer:

Yes, this provide enough evidence to show a difference in the proportion of households that own a​ desktop.

Step-by-step explanation:

We are given that National data indicates that​ 35% of households own a desktop computer.

In a random sample of 570​ households, 40% owned a desktop computer.

<em><u>Let p = population proportion of households who own a desktop computer</u></em>

SO, Null Hypothesis, H_0 : p = 25%   {means that 35% of households own a desktop computer}

Alternate Hypothesis, H_A : p \neq 25%   {means that % of households who own a desktop computer is different from 35%}

The test statistics that will be used here is <u>One-sample z proportion</u> <u>statistics</u>;

                                  T.S.  = \frac{\hat p-p}{{\sqrt{\frac{\hat p(1-\hat p)}{n} } } } }  ~ N(0,1)

where, \hat p = sample proportion of 570​ households who owned a desktop computer = 40%

            n = sample of households = 570

So, <u><em>test statistics</em></u>  =  \frac{0.40-0.35}{{\sqrt{\frac{0.40(1-0.40)}{570} } } } }

                               =  2.437

<em>Since, in the question we are not given with the level of significance at which to test out hypothesis so we assume it to be 5%. Now at 5% significance level, the z table gives critical values of -1.96 and 1.96 for two-tailed test. Since our test statistics doesn't lies within the range of critical values of z so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which we reject our null hypothesis.</em>

Therefore, we conclude that % of households who own a desktop computer is different from 35%.

3 0
3 years ago
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