What is the problem what am I supposed to do?
Answer:
The correct answer is B. Africa
Explanation:
African Institute for Mathematical Sciences (AIMS) was founded in 2003 having its first center in Cape Town, South Africa. AIMS provides training for Africa's talented university graduates needed to enter technical professions or pursue graduate studies in technical fields. The Next Einstein Initiative (NEI) is a strategic plan to build on the success of the first AIMS centre and create a coordinated pan-African network of 15 AIMS centres by 2020, producing 750 well-qualified graduates per annum. AIMS won the Google's Project 10^100 and also the founder of AIMS won the TED Prize and announced his vision to unlock scientific talent across Africa.
Lowercase a is decimal 97 ; upper case is decimal 65
It's easier to think of them in octal, however: a = octal 141, and A is octal 101
octal to binary is easy, each digit is three bits.
141 = 001 100 001
101 = 001 000 001
So, how many bits are changed above?
Answer:
Flaws and limitations identified in this program includes;
1.There was a not necessary usage of variable retrieval. Would have made use of canConvert.
2. Looking at the program, one will notice numerous typos. One of which is the fact that in JAVA we make use of Boolean instead of bool.
3.We rather use Integer.parseInt in JAVA and not Int16, cant make use of Int16.
4. The exception cant be printed
5. JAVA makes use of checkConversion instead of convertNumber as used in the program.
6. It cant work for decimal numbers, 0 and big integers.
Explanation:
See Answer for the detailed explaination of the flaws and limitations identified in the program.
Answer:
CT = 470nF + 1000nF = 1470nF or 1.47μF
Explanation:
When capacitors are connected together in parallel the total or equivalent capacitance, CT in the circuit is equal to the sum of all the individual capacitors added together. This is because the top plate of capacitor, C1 is connected to the top plate of C2 which is connected to the top plate of C3 and so on. The same is also true of the capacitors bottom plates. Then it is the same as if the three sets of plates were touching each other and equal to one large single plate thereby increasing the effective plate area in m2.
Since capacitance, C is related to plate area ( C = ε(A/d) ) the capacitance value of the combination will also increase. Then the total capacitance value of the capacitors connected together in parallel is actually calculated by adding the plate area together. In other words, the total capacitance is equal to the sum of all the individual capacitance’s in parallel. You may have noticed that the total capacitance of parallel capacitors is found in the same way as the total resistance of series resistors.
The currents flowing through each capacitor and as we saw in the previous tutorial are related to the voltage.
