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erica [24]
3 years ago
10

Hi I paid for brainy plus, but it says the it can't renew and try paying for it again but it won't work. Please help

Computers and Technology
1 answer:
Scorpion4ik [409]3 years ago
8 0

Answer:

Contact CS, ( customer support ) They should be able to help you. Go to this link for more info. brainly.com/contact/index

Explanation:

You might be interested in
Which of the following is not a method for opening Word software?
timofeeve [1]

Answer:

right clicking on the desktop and selecting "view"

Explanation:

Some of the methods for opening Microsoft Word software include;

using the Ms. Word icon on the task-bar

searching for the Ms. Word program if you are using the Widows operating system

using the Ms. Word icon on the desktop

On the other hand, right clicking on the desktop and selecting "view" is a procedure for changing icon settings on desktop,

8 0
3 years ago
Read 2 more answers
Help with some questions. Thank you!
Oksana_A [137]

Answer:

1. E: II and III only

2. A: (int)(Math.random() * (upper − lower) ) + lower

3. A: The value of answer is N

4. E: while( !(userGuess == secretNumber) && numGuesses <= 15 )

5. C: 21

Explanation:

1. Which of the following is equivalent to while(userGuess != secretNumber)?

I. while( userGuess < secretNumber && userGuess > secretNumber)  

NO - This will test until the userGuess is smaller AND greater than the secretNumber, at the same time... so that condition will never be true.

II. while( userGuess < secretNumber || userGuess > secretNumber)

YES - This will test the value of userGuess and see if it's smaller OR greater than secetNumber.  So, it will loop until the user guesses right.

III. while( !(userGuess == secretNumber) )

YES, this will negate the match with the secretNumber.  In order words, if it's not a match, it will return true... so the loop will run until it finds a false condition (a match).

As you can see, only II and III are valid.

2.  If the lower limit were inclusive and the upper limit exclusive, which expression would properly generate values for the secret number?

A: (int)(Math.random() * (upper − lower) ) + lower

Since the lower limit is INCLUSIVE, we mustn't add one to the lower limit.  Also, the Math.random() function returns a value that matches our needs; it returns a value between [0,1[ (meaning the 0 is included, but not the 1).

Assuming the (int) caster does return only the integer portion doing a round down of the result, we'll be perfect.

3. What conclusion can be made about the state of the program when the while loop terminates?

while(!answer.equals( "N"))

{.....

A: The value of answer is N

The condition in the loops reads as "While the negation of the answer being 'N', loop".  If the answer equals 'N' then the method should return true... which will be negated by the '!' operator, causing the condition to be false. Thus we know that if the loop ends, the value of answer contains 'N', any other value will keep the loop going.

4. Assuming numGuesses is initialized to 1, how would the while statement be modified to include an extra criterion limiting the number of guesses to 15?

E: while( !(userGuess == secretNumber) && numGuesses <= 15 )

This modified condition will first test to see if the user has guessed the secretNumber (if he has, the first sub-parenthesis will be true... so the left side of the && operator will be false due to the negation operator.  The right side of the && operator will check to see how many tries have been attempted. Since the counter starts at 1, it needs to go up to 15 inclusively... so the <= is the right comparison operator.

5. After execution of the following code segment, what will be displayed?

int x = 1;

while(x < 18)

{

x += 5;

}

System.out.println(x);

C: 21

The x variable is initialized with 1... then enters the loop, in which it is incremented by 5 at each passage.

So after first passage, x = 6

After second passage, x = 11

After third passage, x = 16

After fourth passage, x = 21

Cannot enter the loop again because 21 > 18.

So, it will print out the value of 21.

3 0
3 years ago
Test if the word mold is stored in the variable word. Computer science.
Andre45 [30]

Answer:

word = str("Enter a word: ")

if "mold" in word:

 print("Mold is in the variable word.")

else:

 print("Mold is not in the variable word.")

5 0
3 years ago
. Consider the problem of finding the largest element in a list of n elements. What will be the basic operation of an algorithm
natali 33 [55]

Answer:

Comparison.

Explanation:

When we have to find a largest in a list of n elements.First we have to iterate over the list so we can access all the elements of the list in one go.Then to find the largest element in the list we have to initialize a variable outside the loop with the minimum value possible and in the loop compare each element with this value,if the element is greater than the variable assign the element to the variable.Then the loop will find the largest element and it will be the variable.

4 0
3 years ago
? An attempt to harm damage or cause threat to a system or network is broadly termed as
Radda [10]

Answer:

A cyber attack or hacking

Explanation:

6 0
3 years ago
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