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a_sh-v [17]
3 years ago
9

−1.26×n=−10.08 n=? lololololololololololol

Mathematics
1 answer:
Verdich [7]3 years ago
7 0
N= 8. The 8 must be positive due to the fact if it were negative your answer would be 10.08 and not -10.08. You find your answer by diving -10.08 by -1.26. A negative divided by a negative is a positive.
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The length of a rectangle is 8 inches longer than half of its width.The area of the rectangle is 18 square inches.How many inche
SOVA2 [1]

Answer:

The correct answer is 2 inches.

Step-by-step explanation:

Let l inches and w inches be the length and width of a rectangle respectively.

According to the given problem, l - 8 = \frac{w}{2}.

Area of the rectangle is given to be, according to the question, 18 square inches.

Thus l × w = 18

⇒ l × (2l - 16) = 18

⇒ 2 l^{2} - 16l - 18 = 0

⇒  l^{2} - 8l - 9 = 0

⇒ ( l - 9) ( l + 1) = 0

The possible values of l are 9 and -1. As the length cannot be equal to -1, thus the value of the length is 9 inches.

Width of the rectangle is 2 inches.

5 0
3 years ago
(2x - 3y)(4x - y)<br> simplify for me
Galina-37 [17]
8x^2-14xy+3y^2 is the answer
5 0
3 years ago
What is the smallest and largest perimeter of a polygon with an area of 20?
DENIUS [597]

Answer:

The polygon with the smallest perimeter is the megagon

The polygon with the largest perimeter is the triangle

Step-by-step explanation:

An equilateral triangle with area = 20 has

0.5× a²×sin60 = 20

a= 6.796

Hence, perimeter = 20.39

A square of area 20 has perimeter= 4×√20 = 17.9

A regular pentagon of area = 20 has perimeter = 3.41 × 5 = 17.05

Hence as the number of sides is increasing, the ratio of the Area to the Perimeter also increases

Therefore, a triangle has the largest perimeter with an area of 20 while a megagon with a million sides has the smallest perimeter with an area of 20.

4 0
3 years ago
Start at 51/2 add 1 1/5
IgorC [24]

51/2 = 25.5

11/5 = 2.2

25.5 + 2.2 = 27.7 or 27 7/10

3 0
3 years ago
Read 2 more answers
On a class trip, there were 45 more girls than boys. the total number of students on the trip was 215. write and solve an equati
Evgesh-ka [11]
(b)+(b+45)=215
b = # of boys
there are 45 more girls than boys and 215 students total.
minus 45 on both sides leaving you with
(b)+(b)=170
combine like terms leaving you with
2b=170
divide both sides by 2
b=85
there were 85 boys
85+45=130
(the 45 for the # of girls more than boys)
there were 130 girls.
3 0
3 years ago
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