All categories

4 years ago

−1.26×n=−10.08 n=? lololololololololololol

1 answer:

7 0

N= 8. The 8 must be positive due to the fact if it were negative your answer would be 10.08 and not -10.08. You find your answer by diving -10.08 by -1.26. A negative divided by a negative is a positive.

You might be interested in

30 points With explanation plz?

rosijanka [135]

Answer:

girl. . I wanna say 80 but don't count on my answer. hopefully I helped

5 0

4 years ago

The owner of a restaurant is reviewing customer complaints. In a random sample of 227 complaints, 57 complaints were about the s

iragen [17]

Answer:

$0.1375$ to $0.3624$

Step-by-step explanation:

Given :The owner of a restaurant is reviewing customer complaints. In a random sample of 227 complaints, 57 complaints were about the slow speed of the service.

To Find :Create a 95% confidence interval for the proportion of complaints that were about the slow speed of the service.

Solution:

n = 227

x = 57

Formula of confidence for proportion: $\widecap{p}-z_{\frac{\alpha}{2}}\sqrt{\frac{\widecap{p}\widecap{q}}{n}}$ to $\widecap{p}+z_{\frac{\alpha}{2}}\sqrt{\frac{\widecap{p}\widecap{q}}{n}}$

$\widecap{p}=\frac{x}{n}$

$\widecap{p}=\frac{57}{227}$

$\widecap{p}=0.25$

$\widecap{q}=1-\widecap{p}$

$\widecap{q}=1-0.25$

$\widecap{q}=0.75$

z at 95% is 1.96

Substitute the values in the formula :

Confidence for proportion: $0.25-1.96\sqrt{\frac{0.25 \times 0.75}{57}}$ to $0.25+1.96\sqrt{\frac{0.25 \times 0.75}{57}}$

Confidence for proportion: $0.1375$ to $0.3624$

Hence 95% confidence interval for the proportion of complaints that were about the slow speed of the service is $0.1375$ to $0.3624$

6 0

3 years ago

Read 2 more answers

Mama Mia’s Pizza sells medium pizza for $7 and charges a $2 delivery fee per order. Which describes this relationship?

serious [3.7K]

a non-proportional function with a y-intercept of 2

5 0

3 years ago

Describe the graph of the function f(x) = x3 − 11x2 + 36x − 36. Include the y-intercept, x-intercepts, and the shape of the grap

Kamila [148]

For a polyonomial
P(x)=ax^n+bx^(n-1)...zx^0
when n is odd, the endpoints of the graph point in oposite directions
when n is even, the endpoints of the graph point in same direction

a is the leading term
when a is positive and:
1. n is odd, the graph goes from bottom left to top right
2. n is even, the graph goes from top left to top right

when a is negative and:
1. n is odd, the graph goes from top left to bottom right
2. n is even, the graph goes from bottom left to bottom right

xintercept is where the line crosses the x axis or when y=0
yintercept is where the line crosses the y axis or when x=0

f(x)=1x^3-11x^2+36x-36
leading term is positive and odd degree

graph goes from bottom left to top right, has 1 inflection point

yint, sub 0 for all x's
f(0)=0^3-11(0)^2+36(0)-36
yintercept is y=-36 or (0,-36)

xintercept
set function equal to zero
0=x^3-11x^2+36x-36
factor
0=(x-2)(x-3)(x-6)
x=2,3,6
xintercepts are at x=2,3,6 or (2,0), (3,0) and (6,0)

4 0

3 years ago

Read 2 more answers

Hyperbola Question:

AveGali [126]

Answer:

$\dfrac{x^{2}}{1210000 } - \dfrac{y^{2}}{5759600} = 1$

Step-by-step explanation:

A hyperbola is a curve for which the difference of the distances |d₂ - d₁| of any point P from the foci is constant.

The definition leads to the equation

$\dfrac{x^{2}}{a^{2}} - \dfrac{y^{2}}{b^{2}} = 1$

1. Calculate the value of a²

Assume the neighbours are at the foci A and B.

The explosion is farther from B than from A, so it occurred on the right branch of the hyperbola.

Then AB = 1 mi = 5280 ft

and the distance from the focus to the y-axis is

c = 2640

The vertices are (±a,0).

The speed of sound is 1100 ft/s, so B is 2200 ft further from the explosion.

The distance from A to the vertex V₁ is c - a. Then

AB = 2200 + 2(c - a) = 2200 -2(2640 - 2a) = 2200 +5280- 2a = 5280

2a = 2200

a = 1100

a² = 1 210 000

2. Calculate the value of b²

$\begin{array}{rcl}a^{2} + b^{2} & = & c^{2}\\1100^{2} + b^{2} & = & 2640^{2}\\b^{2} & = & 2640^{2} - 1100^{2}\\& = & 6969600 - 1210000\\& = & \mathbf{5759600}\\\end{array}$

3. Write the equation for the hyperbola

$\mathbf{\dfrac{x^{2}}{1210000 } - \dfrac{y^{2}}{5759600}} = \mathbf{1}$

5 0

4 years ago