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Trava [24]
3 years ago
8

Please help me!!!!with this!!!

Mathematics
1 answer:
kodGreya [7K]3 years ago
8 0

5x+9-3x=11

5x-3x=11-9

2x=2

2:2

x=1

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A box is being pulled by two people. The ropes make angles of 40° and 55° with the direction of motion of the box. If the resu
Andrew [12]

Answer:

  • 575.6 N at 40°
  • 451.7 N at 55°

Step-by-step explanation:

Angles are measured from the direction of motion, so the "force made good" is the force in the rope multiplied by the cosine of the angle. If the forces in the ropes (in Newtons) are represented by x and y, then we have ...

  x·cos(40°) +y·cos(55°) = 700

In order for the resultant to be in the direction of motion, the forces perpendicular to the direction of motion must cancel.

  x·sin(40°) - y·sin(55°) = 0

Here, we have assumed that the positive direction for measuring 40° is the negative direction for measuring 55°. That is, the angles are measured in opposite directions from the direction of motion.

Any of the usual methods for solving systems of linear equations can be used to solve this set. My preference is to use a graphing calculator. It gives the answers summarized above.

4 0
4 years ago
I need the hour and the minuts too thank you
hammer [34]

Answer:

5hrs & 30mins

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
How to change a number written in scientific notation to standard notation.
saveliy_v [14]
In scientific notation, a number is usually?.?*10^??
for example:
1.3*10^-2
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6 0
4 years ago
Can someone help pls
zhenek [66]
So you must be reflecting over the y=x line so your quadrates would be (4,-2) (5,-4) (3,-9)
7 0
3 years ago
Question Help
ValentinkaMS [17]

Step-by-step explanation:

We assume that the advertising rates in this journal for full-page ads is x ($/ad); the rate for half-page ads is y ($/ad).

The revenue for 3 full page ads are: 3x ($)

The revenue for 5 half page ads are: 5y ($)

One issue of a journal has 3 full-page ads and 5 half-page ads, generating $6340.

=> The total revenue for 3 full page and 5 half page ads are $6340

=> 3x + 5y = 6340

The revenue for 4 full page ads are: 4x ($)

The revenue for 4 half page ads are: 4y ($)

One issue of a journal has 4 full-page ads and 4 half-page ads, generating $6625.

=> The total revenue for 4 full page and 4 half page ads are $6625

=> 4x + 4y = 6625 (1)

We have:

+) 3x + 5y = 6340

=> 5y = 6340 - 3x

=> y = (6340 - 3x)/5 = 1268 - 0.6x

Replace <em>y = 1268 - 0.6x </em>into (1), we have:

4x + 4y = 6625

⇔4x + 4(1268 - 0.6x) = 6625

⇔ 4x + 5072 - 2.4x = 6625

⇔ 1.6x = 1553

⇔ x = 1553/1.6 = 970.625

=> y = 1268 - 0.6x = 1268 - 0.6*970.625= 1268 - 582.375 = 685.625

So the advertising rate for full page ads is $970.625, for half-page ads is $685.625

7 0
4 years ago
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