If you’re using distributive property you’re answer would be... -6x+12 hope I helped !
Answer:i think the answer is something
Step-by-step explanation:
Proving a relation for all natural numbers involves proving it for n = 1 and showing that it holds for n + 1 if it is assumed that it is true for any n.
The relation 2+4+6+...+2n = n^2+n has to be proved.
If n = 1, the right hand side is equal to 2*1 = 2 and the left hand side is equal to 1^1 + 1 = 1 + 1 = 2
Assume that the relation holds for any value of n.
2 + 4 + 6 + ... + 2n + 2(n+1) = n^2 + n + 2(n + 1)
= n^2 + n + 2n + 2
= n^2 + 2n + 1 + n + 1
= (n + 1)^2 + (n + 1)
This shows that the given relation is true for n = 1 and if it is assumed to be true for n it is also true for n + 1.
<span>By mathematical induction the relation is true for any value of n.</span>
Answer:
Step-by-step explanation:
Out of the given options, is the only fraction that is improper. All other options are not improper. Therefore, would not belong is the given group of fractions.
Hope this helps.
Sorry, but I have no idea what your "<span>eaqkesbnnn" means.
</span>
If you were supposed to add 0.16 and 0.45, the correct answer would be 0.61.
