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3 years ago

15

6. Find the value of y. 5 16

1 answer:

Svetllana [295]3 years ago

4 0

3.59999
or 3.6
hopefully this helps you!

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A five-digit number starts with a number between 4-9 in the first position, with no restrictions on the remaining 4 digits. a

Maurinko [17]

Answer:

(a) $Pr = 0.3024$

(b) $Pr = 0.6976$

(c) $Pr = \frac{^9P_{n-1}}{10^{n-1}}$

Step-by-step explanation:

Given

$Start = \{5,6,7,8\}$ i.e. between 4 and 9

$n(Start) =4$

$Digits = 5$

Solving (a): Probability that each of the 5 digit are different

Since there is no restriction;

The total possible selection is as follows:

$First\ digit = 4$ (i.e. any of the 4 start digits)

$Second\ digit = 10\\$ (i.e. any of the 10 digits 0 - 9)

$Third\ digit = 10$ (i.e. any of the 10 digits 0 - 9)

$Fourth\ digit = 10$ (i.e. any of the 10 digits 0 - 9)

$Fifth\ digit = 10$ (i.e. any of the 10 digits 0 - 9)

So, the total is:

$Total = 4 * 10 * 10 * 10 * 10$

$Total = 40000$

For selection that all digits are different, the selection is:

$First\ digit = 4$ (i.e. any of the 4 start digits)

$Second\ digit = 9$ (i.e. any of the remaining 9)

$Third\ digit = 8$ (i.e. any of the remaining 8)

$Fourth\ digit = 7$ (i.e. any of the remaining 7)

$Fifth\ digit = 6$ (i.e. any of the remaining 6)

So:

$Selection =4 * 9 * 8 * 7 * 6$

$Selection =12096$

So, the probability is:

$Pr = \frac{Selection}{Total}$

$Pr = \frac{12096}{40000}$

$Pr = 0.3024$

Solving (b): At least 1 repeated digit

The probability calculated in (a) is the all digits are different i.e. P(None)

So, using laws of complement

We have:

$P(At\ least\ 1) = 1 - P(None)$

So, we have:

$Pr= 1 - 0.3024$

$Pr = 0.6976$

Solving (c): An expression to model the probability.

<em>Using (a) as a point of reference, we have;</em>

$Pr = \frac{Selection}{Total}$

Where

$Selection =4 * 9 * 8 * 7 * 6$ ---- for selection of 5 i.e. n = 5

$Total = 4 * 10 * 10 * 10 * 10$

$Selection =4 * 9 * 8 * 7 * 6$

This can be rewritten as:

$Selection = 4 * ^9P_4$

4 can be expressed as: 5 - 1

So, we have:

$Selection = (5-1) *^9P_{5-1}$

Substitute n for 5

$Selection = (n-1) *^9P_{n-1}$

$Selection = (n-1)^9P_{n-1}$

$Total = 4 * 10 * 10 * 10 * 10$

This can be rewritten as:

$Total = 4 * 10^4$

$Total = (5-1) * 10^{5-1}$

$Total = (n-1) * 10^{n-1}$

$Total = (n-1) 10^{n-1}$

So, the expression is:

$Pr = \frac{(n-1)^9P_{n-1}}{(n-1)10^{n-1}}$

$Pr = \frac{^9P_{n-1}}{10^{n-1}}$

<em>Where n represents the digit number</em>

5 0

3 years ago

Please help me solve this

In-s [12.5K]

Step-by-step explanation:

Erase the dot points you already have. We are supposed to substitute those values in the right side of problem 1 into the function as x.

For example if x=-4

$- ( - 4) + 5 = 9$

If x=-2

$- ( - 2) + 5 = 7$

If x=0

$0 + 5 = 5$

$- 2 + 5 = 3$

$- 4 + 5 = 1$

So our point should be

-4,9

-2,7

0,5

-2,3

-4,1.

The range is all possible y values in a function. Since this is discrete and we are given the domain, our range will just be the y value of the points you graphed.

(9,7,5,3,1)

5 0

2 years ago

-3(-4r - 5)<br> combining like terms

svp [43]

Answer:

r

=

1

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Solve f(-7) for f(x) = 17 – X

grigory [225]

Answer:

f(-7) = 24

Step-by-step explanation:

Step 1: Identify the Function

f(x) = 17 - x is the function

Step 2: Set x to -7 in the function

f(-7) = 17 - (-7)

f(-7) = 17 + 7

f(-7) = 24

Answer: f(-7) = 24

8 0

3 years ago

In a glide reflection, what comes first and what comes second?

NISA [10]

Answer:

A glide reflection is a composition of transformations.In a glide reflection, a translation is first performed on the figure, then it is reflected over a line. Therefore, the only required information is the translation rule and a line to reflect over. ... The first one is a translation rule.

3 0

3 years ago