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4vir4ik [10]
3 years ago
14

There are 2 parts to it . part a and part b .​

Mathematics
1 answer:
frez [133]3 years ago
8 0

Answer:

2x^{2} - y^{2} +5xy - 2y

A) 4 terms

B) 0 negatives

Step-by-step explanation:

Combine the like terms

So -3x squared + 5x squared = 2x squared

2y squared - 3y squared = -1y squared

There is only one term with 5xy so you leave it as it is

There is only one term with 2y so you leave it as it is

Now put this in an equation and use the negative and positive signs as addition or subtraction signs.

So it looks like:

2x^{2} - y^{2} +5xy - 2y

Hoped This Helped!!!

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The sum of three consecutive integers is 21 larger than twice the smallest integer. find the integers.
Darya [45]
Let the integers be x-1, x, x+1.

Given,

x -1 + x + x + 1 = 21 + 2(x - 1)

3x = 21 + 2x - 2

x = 19

Hence, the three integers are 18, 19 and 20.
7 0
3 years ago
Problem Page
Orlov [11]

If order matters, then there are 12 ways to do this

If order does not matter, then there are 6 ways to do this

===========================================

We have 4 choices for the first slot and 3 choices for the next (we can't reuse a letter) so that's where 4*3 = 12 comes from

If order doesn't matter, then something like AB is the same as BA. So we are doubly counting each possible combo. To fix this, we divide by 2: 12/2 = 6

To be more formal, you can use nPr and nCr to get 12 and 6 respectively (use n = 4 and r = 2)

7 0
2 years ago
While at a bakery, Chad decides to purchase some cupcakes and brownies to share with his friends. He can spend no more than $13,
son4ous [18]

Answer:

13 divided by 6

Step-by-step explanation:

5 0
2 years ago
75% of something = 342<br>Need answer quick
Ostrovityanka [42]
The answer is 456

This the answer 456
8 0
3 years ago
Which quadratic equation has the roots -1+4i and -1-4i
AysviL [449]

Answer:

C

Step-by-step explanation:

Solve the quadratic in answer choice C using the quadratic formula:

x=\frac{-b+/-\sqrt{b^2-4ac} }{2a}.

Here a=1, b=2, and c=17.

Substitute and you'll have:

x=\frac{-b+/-\sqrt{b^2-4ac} }{2a} =\frac{-2+/-\sqrt{(-2)^2-4(1)(17)} }{2(1)}=\frac{-2+/-\sqrt{4-68}}{2)}

\frac{-2+/-\sqrt{-64} }{2}=\frac{-2+/-8i }{2}=-1+/- 4i


6 0
3 years ago
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