First one:
(3x^2+5y^2)^3
Step 1: Use the binomial theorem to expand
(3x^2)+3(3x^2)^2(5y^2)+3(3x^2)(5y^2)2+(5y^2)^3
Step 2: Simplify each term
27(x^2)^3+3(3x^2)^2(5y^2)+3(3x^2)(5y^2)^2+(5y^2)^3
Step 3: Multiply the exponents
27x^6+27x^4(5y^2)+3(3x^2)(5y^2)^2+(5y^2)^3
27x^5+135x^4y^2+3(3x^2)(5y^2)^2+(5y^2)^3
Keep going to get the final answer:
27x^6+135x^4y^2+225x^2y^4+125y^6
2nd question: (2y^3-5x)^2
Do the same thing...step by step
Answer: 4y^6-20xy^3+25x^2
Answer:
y
=
11
+
√
73/
4 ,
11
−
√
73
/4
Step-by-step explanation:
Answer:
-121.4.
Step-by-step explanation:
2+4+-56×43÷20+46-53 Multiply and divide are done first:
= 2+4 + -2408 / 20 + 46 - 53
= 2 + 4 - 120.4 + 46 - 53
= -114.4 - 7
= -121.4.
B??? I’m so srry if I’m wrong but try