1) Measures of the middle of the data are called measures of ________

Find the greatest possible error for the measurement 0.991 g.

Veronika [31]

Explanation:

Any calibration scale consists of markings indicating calibrated values. The ‘space’ between the marks (lines) is the area of uncertainty with respect to the calibration.

Thus, the possible error is always one-half of the value between the markings, because ON either one you have a calibrated value. In between, no matter how close you think you can “judge” the distance, there is no calibrated reference point, so the ‘error’ of stating a value is +/- the value of half of the calibration accuracy. 0.991 is accurate (assuming that is the calibration limit), and 0.992 or 0.990 would also be “accurate”. The possible error is the +/- 0.0005 beyond that third digit that might be more to one side or the other.

That means the measured value of 0.991g could be between 0.9905g and 0.9915g.

4 0

3 years ago

Read 2 more answers

Write an equation of the line passing through both of these points: (-3, 1) and (0,3). The equation should be in slope-intercept

creativ13 [48]

The answer is
y=2/3x+3

8 0

3 years ago

What is the image of (1, -6) for a 180° counterclockwise rotation about the origin?

a_sh-v [17]

Answer: option b

Step-by-step explanation:

It is important to know that, by definition, the rule for 180 degrees counterclockwise rotation is:

$(x,y)$ → $(-x,-y)$

Therefore, given the point (1, -6) we can find the image obtained for for a 180° counterclockwise rotation about the origin by applying the rule mentioned before.

Then, the image is:

$(1,-6)$ → $(-(1),-(-6))=(-1,6)$