Julio's father is 4 times as old as Julio. The sum of their ages is no less than 55.
1 answer:
Call (F) the age of the father and (J) the age of Julio
The F & J are related in this way: F=4J
Now you have a restriction in the form of inequality: The sum of both ages has to be greater or equal than 55.
Algebraically that is: F + J ≥ 55
You can substitute F with 4J to find the solution for J:
4J + J ≥ 55
5J ≥ 55
Now divide both sides by 5
5J/5 ≥ 55/5
J ≥ 11
That Imposes a lower boundary for the value of J of 11, meaning that the youngest age of Julio can be 11
You might be interested in
Answer:
11x + 4d
Step-by-step explanation:
8x + 9d + 3x -5d
To simplify this we have to group them by their like terms i.e.
= 8x + 3x + 9d - 5d
= 11x + 4d
Mark brainliest
An
chọn A
Step-by-step explanation:
3x-5>= 4x-3
<=>x <= -2( -2;-3;-5)
Answer:
=
2
−
1
4
2
−
1
4
=
=
−
5
−
5
Step-by-step explanation:
154=-32-24x+24
154+32-24=-24x
162=-24x
162/-24=-24x/-24
X=-6.75
Answer:
y - 5 = -(x + 5)
y - 5 = -x - 5
y = -x