Julio's father is 4 times as old as Julio. The sum of their ages is no less than 55.
1 answer:
Call (F) the age of the father and (J) the age of Julio
The F & J are related in this way: F=4J
Now you have a restriction in the form of inequality: The sum of both ages has to be greater or equal than 55.
Algebraically that is: F + J ≥ 55
You can substitute F with 4J to find the solution for J:
4J + J ≥ 55
5J ≥ 55
Now divide both sides by 5
5J/5 ≥ 55/5
J ≥ 11
That Imposes a lower boundary for the value of J of 11, meaning that the youngest age of Julio can be 11
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Answer:
17
Step-by-step explanation:
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Hey there!
Hope this helps!
Answer:
A(3) = 6
A(5) = 18
A(11) = 54
PLS MARK AS BRAINLIEST
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You have to multiply 7 by 2b and by 5 to get 14b+35