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3 years ago

Write an algibraic equasion for the word senentces - a number increased by 7.9 is 8.3

Mathematics

2 answers:

antoniya [11.8K]3 years ago

5 0

X+7.9=8.3 that is the answer.

Tasya [4]3 years ago

4 0

Answer:

y+7.9=8.3

Step-by-step explanation:

A number means any variable

Increased means the '+' sign

and since it's increased by 7.9 then that number goes on the other side of the '+' sign

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1/2 × s for s = 3/10

Sauron [17]

Answer:

Step-by-step explanation:

1/2s......when s = 3/10

1/2 * 3/10 = 3/20

8 0

3 years ago

Read 2 more answers

What is the solution of the following system of equation x +y = 2 x - y = 4

sergiy2304 [10]

Answer:

X+y=2

x-y=4

(x+y)+(x-y)= 2+4

X+y+x-y=6

2x=6

X=3

3+y=2 or 3-y=4

Y=-1

3+(-1)=2 or 3-(-1)=4

Step-by-station:

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3 years ago

An item is regularly priced at $65. Jina bought it on sale for 20% off the regular price. How much did Jina pay?

Archy [21]

Answer:

20\100. ×65

65-13

52$

8 0

3 years ago

Find the dimensions of the box described. The length is twice as long as the width. The height is 4 inches greater than the widt

valentina_108 [34]

Answer:

Width of box= 2inches

Length of box= 4inches

Height of box= 6inches.

Step-by-step explanation:

Let width of box=x inches

Length of box = twice of width= $2\times x$ = $2x$

Height of box= 4 inches greater than width= $x+4$

Volume of box= 48 cubic inches

We know that the formula of volume of cuboid= $length\times breadth\times height$

Apply the formula

Volume of box= $x\times 2x\times (x+4)$

Volume of cube = $2x^2(x+4)$

$2x^2(x+4)=48$

$x^2(x+4)=24$

$x^3+x^2-24$

Apply inspection method to solve the equation

Put $x=0$

Then we get $-24\neq0$

Hence, x=0 is not the solution of x

Put x=1 in the equation then we get

$-22\neq 0$

Hence x=1 is not the solution of equation.

Put x=2 then we get

$(2)^3+(4)^2-24$

8+16-24=0

Hence, x=2 is the solution of equation .

$(x-2)(x^2+6x+12)$ =0

Now substitute equation $x^2+6x+12$ =0

Sum roots =6

Product of roots=12

When sum of roots is greater than zero and product of roots is greater than zero then value of roots of equation is imaginary.

Hence, the roots of equation $x^2+6x+12=0$ are imaginary.

Lenght , widht and height are dimensions of box therefore, imaginary value are not possible.

Hence, $x=2$ is the only real values of root of equation .Therefore, it is possible and other two imaginary value of roots are not possible .

Widht of box=2 inches

Length of box = $2\times2$ =4inches

Height of box= $x+4$ =2+4=6 inches

4 0

3 years ago

On a journey of 600 km, a train was delayed 1 hour and 30 min after having covered 1/4 of the way. To arrive on time at the dest

MAXImum [283]

Answer:

The train traveled for 32.66 hours.

Step-by-step explanation:

Let the speed of the train was initially for $\frac{1}{4}$ the distance was x km/hr.

So, 150 km the train moved with x km/hr speed and the remaining 450 km the train goes with the speed of (x + 15) km/hr.

Then, the time taken by the train to cover the first 150 km will be $\frac{150}{x}$ hrs.

Therefore, with the actual speed, the train would have covered the 150 km by $(\frac{150}{x} - 1\frac{1}{2}) = (\frac{150}{x} - \frac{3}{2}) = \frac{300 - 3x}{2x}$ hrs.

Now, from the given conditions, we can write the equation as

$4(\frac{300 - 3x}{2x}) = \frac{150}{x} + \frac{450}{x + 15}$

⇒ $2(\frac{300 - 3x}{x}) = 150 \times \frac{4x + 15}{x(x + 15)}$

⇒ (300 - 3x) (x + 15) = 75(4x + 15) {Since x ≠0}

⇒ 300x + 4500 - 3x² - 45x = 300x + 1125

⇒ 3x² + 45x - 3375 = 0

⇒ x² + 15x - 1125 = 0

⇒ $x = \frac{- 15 \pm \sqrt{15^{2} - 4(1)(-1125)}}{2}$ {Applying the quadratic formula}

⇒ x = 26.87 km/hr {Ignoring the negative root}

Therefore, the train traveled for $4(\frac{300 - 3 \times 26.87}{26.87}) = 32.66$ hours. (Answer)

7 0

3 years ago