Answer:
2.63274768567
Step-by-step explanation:
First, note that 3.1415... is p, so 2(3.1415...) is 2pi and 4(3.1415...) is 4pi.
2pi and 4pi are full rotations, which will lead to the same cosine (i.e. cos(x) = cos (x+2pi) = cos(x+4pi) = ... = cos (x+2k*pi)).
So, the expression equals cos0.5 + cos 0.5 + cos0.5 = 3cos0.5 = 3(0.87758256189) = 2.63274768567
I hope this helps! :)
Answer:
ST = 4
Step-by-step explanation:
A segment joining the midpoints of 2 sides of a triangle is half the length of the third side.
ST =
PQ substitute values
- 32 + 9x =
(- 5x + 28) ← multiply both sides by 2 to clear the fraction
- 64 + 18x = - 5x + 28 (add 5x to both sides )
- 64 + 23x = 28 ( add 64 to both sides )
23x = 92 ( divide both sides by 23 )
x = 4
Then
ST = - 32 + 9x = - 32 + 9(4) = - 32 + 36 = 4
Answer:
So, the first three nonzero terms in the Maclaurin series are:

Step-by-step explanation:
From exercise we have the next function y = 6 sec(3x).
We know that Maclaurin series for the function sec x, have the following form:

So, for the given function y = 6 sec(3x), we get:

So, the first three nonzero terms in the Maclaurin series are:

Answer:
2
Step-by-step explanation:
I think the answer is: ACD