All categories

3 years ago

Help! I need some help...

Mathematics

2 answers:

AURORKA [14]3 years ago

8 0

The complement is 38
and the supplement is 128

Effectus [21]3 years ago

4 0

The complementary angle is 38. Since a complementary angles is two sums that equal 90.
The Supplementry angle is 128. Since both of the two angles have to equal 180

You might be interested in

What is the result when the number 86 is decreased by 9%?

Vikki [24]

78.26

Hope this helps!!!

6 0

3 years ago

Can you help me solve 4x+3+x-8

Svetlanka [38]

The answer to your problem is -1x.

6 0

3 years ago

Read 2 more answers

Marcy needs 150 feet of fabric for her project. She uses 20% of it. How many feet of fabric did she use for her project so far?

Nataliya [291]

Answer:

The answer is 120 feet of fabric

4 0

2 years ago

Read 2 more answers

Let T be the plane-2x-2y+z =-13. Find the shortest distance d from the point Po=(-5,-5,-3) to T, and the point Q in T that is cl

GaryK [48]

Answer:

d=10u

Q(5/3,5/3,-19/3)

Step-by-step explanation:

The shortest distance between the plane and Po is also the distance between Po and Q. To find that distance and the point Q you need the perpendicular line x to the plane that intersects Po, this line will have the direction of the normal of the plane $n=(-2,-2,1)$ , then r will have the next parametric equations:

$x=-5-2\lambda\\y=-5-2\lambda\\z=-3+\lambda$

To find Q, the intersection between r and the plane T, substitute the parametric equations of r in T

$-2x-2y+z =-13\\-2(-5-2\lambda)-2(-5-2\lambda)+(-3+\lambda) =-13\\10+4\lambda+10+4\lambda-3+\lambda=-13\\9\lambda+17=-13\\9\lambda=-13-17\\\lambda=-30/9=-10/3$

Substitute the value of $\lambda$ in the parametric equations:

$x=-5-2(-10/3)=-5+20/3=5/3\\y=-5-2(-10/3)=5/3\\z=-3+(-10/3)=-19/3\\$

Those values are the coordinates of Q

Q(5/3,5/3,-19/3)

The distance from Po to the plane

$d=\left| {\to} \atop {PoQ}} \right|=\sqrt{(\frac{5}{3}-(-5))^2+(\frac{5}{3}-(-5))^2+(\frac{-19}{3}-(-3))^2} \\d=\sqrt{(\frac{5}{3}+5))^2+(\frac{5}{3}+5)^2+(\frac{-19}{3}+3)^2} \\d=\sqrt{(\frac{20}{3})^2+(\frac{20}{3})^2+(\frac{-10}{3})^2}\\d=\sqrt{\frac{400}{9}+\frac{400}{9}+\frac{100}{9}}\\d=\sqrt{\frac{900}{9}}=\sqrt{100}\\d=10u$

7 0

3 years ago

What is the answer to this how to work it

Anna007 [38]

9514 1404 393

Answer:

(A) -7

Step-by-step explanation:

The function is continuous if you can draw its graph without lifting your pencil. In this case, that means each of the piecewise function definitions must have the same value at x=3.

x^2 +2 = 6x +k . . . . . must be true at x=3

3^2 +2 = 6(3) +k . . . . substitute 3 for x

9 +2 -18 = k . . . . . . . . subtract 18

k = -7 . . . . . . . simplify

7 0

2 years ago