What is 121 rounding to the nearest 100 and what is 252 rounding to the nearest 100
2 answers:
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Given:
It is given that,
PQ ⊥ PS and
∠QPR = 7x-9
∠RPS = 4x+22
To find the value of ∠QPR.
Formula
As per the given problem PR lies between PQ and PS,
So,
∠QPR+∠RPS = 90°
Now,
Putting the values of ∠RPS and ∠QPR we get,
or,
or,
or,
or,
Substituting the value of in ∠QPR we get,
∠QPR =
or, ∠QPR =
Hence,
The value of ∠QPR is 40°.
