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Art [367]
3 years ago
8

nick have collection of 80 cars.3/5 of his toys are bus.the rest are cars and bike.the number of cars are the three time the num

ber of bikes.how many cars are there.
Mathematics
1 answer:
stiks02 [169]3 years ago
8 0

Answer:

24 cars

Step-by-step explanation:

out of 80 toys, 3/5 are buses- 80 * 3/5 is 48 so there are 48 buses

80 - 48 is 32, 32 of the rest of the toys are cars and bikes

we know that there are 3 times as many cars than bikes, so to find out how many cars and bikes there we can do 3n + n, where n is the number of bikes it also equals 4n

32 = 4n; n = 8

there are 8 bikes, so there are 24 cars

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Alexa and her friends went out for pizza to celebrate the softball team’s victory.  Their total bill for the pizza and drinks wa
Nitella [24]

Answer:

$39

Step-by-step explanation:

32.50:100 × 20 = $6.50

32.50+6.50 = $39

5 0
3 years ago
The piecewise function f(x) is defined below. What is the value of f(–2)?
Usimov [2.4K]
f(-2)=3, because f(x)=3 for -2\leq x\ \textless \ 0
3 0
3 years ago
Read 2 more answers
The length of a rectangular fenced enclosure is 12 feet more than the width. If Farmer Dan has 100 feet of fencing, write an ine
Kitty [74]
Answer:
length = 31 ft
width = 19 ft

Explanation:
Assume that the width of the rectangle is w.
We are given that the length is 12 ft more than the width. This means that the length of the rectangle is w + 12

The perimeter of the rectangle in this case would be:
perimeter = 2 (length + width)
perimeter = 2 (12 + w + w)
perimeter = 24 + 4w

Assume that Dan would use all 100 ft of fencing to surround the yard. This would mean that the largest perimeter is 100 ft.

Therefore:
perimeter = 24 + 4w
100 = 24 + 4w
4w = 100 - 24
4w = 76
w = 19 ft

Since we have calculated that the width of the yard is 19 ft, we can substitute to get the length as follows:
length = 12 + w
length = 12 + 19
length = 31 ft

Hope this helps :)
7 0
3 years ago
Read 2 more answers
I actually need help bhっっっっb
Artyom0805 [142]

How long have you been stuck on this problem???

5 0
3 years ago
A typical virus is a packet of protein and DNA (or RNA) and can be spherical in shape. The influenza A virus is a spherical viru
DochEvi [55]

Answer:

10⁻⁶

Step-by-step explanation:

Since the volume of saliva coughed up by my friend is 0.0100 cm³ and 10⁺⁹ of this volume contains the virus. The volume containing the virus is thus V = 0.0100 cm³ × 10⁺⁹ = 0.0100 × 10⁺⁹ cm³ = 0.0100 × 10⁺⁹ × 10⁻⁶ m³ = 0.0100 × 10⁺¹⁵ m³.

Now, since the flu virus is spherical, its volume is v = 4πr³/3 where r is its radius.

Let n flu viruses be contained in the volume V of flu viruses coughed out by my friend.

So n × v = V

v = V/n

4πr³/3 = V/n

r = ∛(3V/4πn)

substituting the value of V into the equation, we have

r = ∛(3 × 0.0100 × 10⁺¹⁵ m³/4πn)

r = (∛0.03/4πn) × 10⁻⁵ m

r = 0.1336/∛n × 10⁻⁵ m

r = 1.336/∛n × 10⁻⁶ m

Since the factor 10⁻⁶ is found in the radius, the order of magnitude of the influenza virus that have just landed on me are of the order 10⁻⁶

3 0
3 years ago
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