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Art [367]
3 years ago
8

nick have collection of 80 cars.3/5 of his toys are bus.the rest are cars and bike.the number of cars are the three time the num

ber of bikes.how many cars are there.
Mathematics
1 answer:
stiks02 [169]3 years ago
8 0

Answer:

24 cars

Step-by-step explanation:

out of 80 toys, 3/5 are buses- 80 * 3/5 is 48 so there are 48 buses

80 - 48 is 32, 32 of the rest of the toys are cars and bikes

we know that there are 3 times as many cars than bikes, so to find out how many cars and bikes there we can do 3n + n, where n is the number of bikes it also equals 4n

32 = 4n; n = 8

there are 8 bikes, so there are 24 cars

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Industrial engineers periodically conduct "work measurement" analyses to determine the time required to produce a single unit of
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Answer:

a) \bar X =117.8

Median= \frac{117+118}{2}=117.5

The mode on this case is the most repeated value 128 with a frequency of 3

b) Range = Max -Min = 150-88=62

s^2 = 225.334

s= \sqrt{225.334}= 15.011

c) y \pm s

Lower = 117.8 -15.011=102.809

Upper = 117.8 +15.011=132.831

y \pm 2s

Lower = 117.8 -2*15.011=87.797

Upper = 117.8 +2*15.011=147.842

y \pm 3s

Lower = 117.8 -3*15.011=72.787

Upper = 117.8 +3*15.011=162.85

d) For this case we can calculate the position where we have accumulated 70% of the data below.

50*0.7 = 35

So on the position 35th from the dataset ordered we see that the value is 128 and this value would represent the 70th percentile on this case.

Step-by-step explanation:

For this case we consider the following data:

128,119,95,97,124,128,142,98,108,120,113,109,124,132,97,138,133,136,120,112,146,128,103,135,114,109,100,111,131,113,124,131,133,131,88,118,116,98,112,138,100,112,111,150,117,122,97,116,92,122

Part a

For this case we can calculate the mean with the following formula:

\bar X = \frac{\sum_{i=1}^{50} X_i}{50}

And after replace we got \bar X =117.8

In order to calculate the median first we order the dataset and we got:

88  92  95  97  97  97  98  98 100 100 103 108 109 109 111 111 112 112 112 113 113  114 116 116 117 118 119 120 120 122 122 124 124 124 128 128 128 131 131 131 132 133  133 135 136 138 138 142 146 150

The median would be the average between the position 25 and 26 from the data ordered and we got:

Median= \frac{117+118}{2}=117.5

The mode on this case is the most repeated value 128 with a frequency of 3

Part b

the range is defined as the difference between the maximun and minimum so we got:

Range = Max -Min = 150-88=62

The sample variance can be calculated with this formula:

s^2 = \frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}

And after calculate we got: s^2 = 225.334

And the deviation is just the square root of the variance and we got:

s= \sqrt{225.334}= 15.011

Part c

For this case we can construct the interval with 1 , 2 and 3 deviation from the mean like this:

y \pm s

Lower = 117.8 -15.011=102.809

Upper = 117.8 +15.011=132.831

y \pm 2s

Lower = 117.8 -2*15.011=87.797

Upper = 117.8 +2*15.011=147.842

y \pm 3s

Lower = 117.8 -3*15.011=72.787

Upper = 117.8 +3*15.011=162.85

Part d

For this case we can calculate the position where we have accumulated 70% of the data below.

50*0.7 = 35

So on the position 35th from the dataset ordered we see that the value is 128 and this value would represent the 70th percentile on this case.

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