It’s 6
since it’s right at 5 & 7
Imagine the graph of f(x)=|x|. This can only output positive values (

).
Then f(x)=|x|+2 is the same graph shifted upwards by two units meaning it can only output values bigger or equal to than 2. So the range is
Answer:
<em>estimated sales on Wednesday is 19000 pounds.</em>
<em></em>
Step-by-step explanation:
On Monday, he sold 25196 pounds. Estimated to the nearest thousand that is 25000 pounds.
On Tuesday, he sold 18023 pounds. Estimated to the nearest thousand, that is 18000 pounds
Wednesday's sales is unknown. We designate as x
All in all he sold 62409. Estimated to the nearest thousand, that is 62000
The sales on Monday, plus sales on Tuesday, plus sales on Wednesday, must all sum up to the total sales.
25000 + 18000 + x = 62000
43000 + x = 62000
x = 62000 - 43000 = 19000
therefore <em>estimated sales on Wednesday is 19000 pounds.</em>
Apply division by 10 when one tenth of a number is required and apply multiplication by 10 when 10 times of a number is required.
<u>Solution:</u>
Need to determine what operation is required to get one-tenth of a number and 10 times of a number
To get one tenth of a number, divide the number by 10.
For example to get one – tenth of 100, divide it by 10, we get 10 as a result.

To get ten times of a number, multiply the number by 10
For example 10 times of 10 = 10 x 10 = 100
Hence apply division by 10 when one tenth of a number is required and apply multiplication by 10 when 10 times of a number is required.
Answer:
A.)359.2, B.)2.5 uf
Step-by-step explanation:
E / I = R
208 / 1.04 = 200 ohms
2*pi*f*L = Xl
6.28*400*.143 = 359.2 ohm
1 / (2*pi*f*Xc) = c
1 /(6.28*400*159.2) = 2.5 uf