Answer:
Step-by-step explanation:
Remark
My guess is that what is confusing you is not what you have to do, but why it is disguised as g(n)
What you are doing in effect is setting up a table. You are also not certain where the table starts. And that is a problem. I will start it at zero, but it might be 1.
zero
n = 0
g(0) = 34 - 5*0
g(0) = 34
One
n = 1
g(1) = 34 - 5*1
g(1) = 34 - 5
g(1) = 29
Two
g(2) = 34 - 5*2
g(2) = 34 - 10
g(2) = 24
Three
g(3) = 34 - 5*3
g(3) = 34 - 15
g(3) = 19
Four
g(4) = 34 - 5*4
g(4) = 34 - 20
g(4) = 19
Answer
0 1 2 3 4
34 29 24 19 14
BD = 2x-4
But it's also BE - CE + CD
BE is 3x-1
CE is 2x-3
CD is 2
so
BD = 3x-1 -(2x-3) +2
simplified
BD = 1x +4
since BD = BD (obviously), we can also say that the righthand sides of the two equation must be equal
2x -4 = 1x +4
let's solve for x and that put it into either of the 2 equations.
2x -4 = 1x +4
subtract 1x on both sides
x -4 = 4
add 4 on both sides
x = 8
substitute x for its value in 2x -4 = 1x +4
(this way we double check BD in two expressions at once. the equation should come out true, meaning same value for BD in each expression. both sides should be equal).
2*8 -4 = 1*8 +4
12 = 12
seems true
BD is safely 12
I think #4 is 4 but I'm not completely sure
Answer:
And we can find the nnumber of deviations from the mean for each limit given:
So we are 3 deviation from the mean and using the empirical rule we know that within 3 deviations from the mean we have 99.7% of the values
Step-by-step explanation:
Let X the random variable that represent the amount of time it takes him to arrive, and for this case we know the distribution for X is given by:
Where 
and 
We want to find this probability:
And we can use the z score formula given by:
And we can find the nnumber of deviations from the mean for each limit given:
So we are 3 deviation from the mean and using the empirical rule we know that within 3 deviations from the mean we have 99.7% of the values
