Number of experimental pinks drawn / number of experimental picks...
4/(4+24+22)
4/50
2/25 or (8%)
You do 22/7 and put the remainder over 7.
7 times 3 is 21 so the remainder is 1.
The answer is 3 and 1/7. Choice 3.
Answer:
0.81 = 81% probability that a randomly selected student is taking a math class or an English class.
0.19 = 19% probability that a randomly selected student is taking neither a math class nor an English class
Step-by-step explanation:
We solve this question working with the probabilities as Venn sets.
I am going to say that:
Event A: Taking a math class.
Event B: Taking an English class.
77% of students are taking a math class
This means that
74% of student are taking an English class
This means that
70% of students are taking both
This means that
Find the probability that a randomly selected student is taking a math class or an English class.
This is , which is given by:
So
0.81 = 81% probability that a randomly selected student is taking a math class or an English class.
Find the probability that a randomly selected student is taking neither a math class nor an English class.
This is
0.19 = 19% probability that a randomly selected student is taking neither a math class nor an English class
the answer is 2
there are 13 days, 6x2=12. so the answer is 2.
Answer:
280
Step-by-step explanation:
when you estimate your problem becomes 4x70 so the answer is 280