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pychu [463]
3 years ago
12

You take a bite out of a

Mathematics
1 answer:
Luda [366]3 years ago
8 0
To solve this problem you must follow the proccedure below:

 a<span>. Find the perimeter and area of the cracker remaining: 

 The perimeter of  a quarter circle is:

 P=(</span>πr/2)+2r
 P=(πx3 cm/2)+2(3 cm)
 P=10.71 cm

 The perimeter of <span>the cracker remaining is:
</span><span>
 Pt=3 cm+6 cm+3 cm+10.71 cm
 Pt=22.71 cm

 The area of a quarter circle is:

 A=</span>πr²/4
 A=π(3 cm)²/4
 A=7.06 cm²
<span>
 The area of</span><span>of the cracker remaining is:
</span><span>
 At=Area of a square-Area of quarter circle
 At=L</span>²-(πr²/4)
 At=(6 cm)²-(π(3 cm)²/4)
 At=28.93 cm²
<span>
 b. About how many bites can you get from the entire cracker?</span> 

 Number of bites=L²/(π(3 cm)²/4)
 Number of bites=5
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