You take a bite out of a

Mathematics

1 answer:

Luda [366]3 years ago

8 0

To solve this problem you must follow the proccedure below:

a. Find the perimeter and area of the cracker remaining:

The perimeter of a quarter circle is:

P=(πr/2)+2r
P=(πx3 cm/2)+2(3 cm)
P=10.71 cm

The perimeter of the cracker remaining is:

Pt=3 cm+6 cm+3 cm+10.71 cm
Pt=22.71 cm

The area of a quarter circle is:

A=πr²/4
A=π(3 cm)²/4
A=7.06 cm²

The area ofof the cracker remaining is:

At=Area of a square-Area of quarter circle
At=L²-(πr²/4)
At=(6 cm)²-(π(3 cm)²/4)
At=28.93 cm²

b. About how many bites can you get from the entire cracker?

Number of bites=L²/(π(3 cm)²/4)
Number of bites=5

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