Given:
The length of the rectangle = 16 ft
The width of the rectangle = 12 ft
The diameter of the semicircle = 12 ft
To find the area of the given figure.
Formula
where,
be the area of the given figure
be the area of the rectangle
be the area of the semicircle.
- The area of the rectangle =
where, l be the length and b be the width - Area of the semicircle =
, r be the radius of the semicircle.
Now,
The radius of the semicircle r = 6 ft
Putting, r=6, l=16 and b= 12 we get,
sq ft
or, 
sq ft
sq ft
or, 
sq ft
So,
sq ft
= 248.52 sq ft
Rounding off to the nearest tenth, we get;
A=248.5 sq ft.
Hence,
The area of the composite figure is 248.5 sq ft.
I think it is <span>Step 1; it should be m∠m + m∠n + m∠o = 90 degrees (corresponding angles) im not that sure but it is the best i got</span>
X=22
Area is found by multiplying (x+7)and (2x-1) together. 22+7=29, 2(22) -1 = 43, 43+29=72
Answer:
The y-intercept is -2
Step-by-step explanation
y= -2 is a horizontal line, so it would not have a slope. Secondly, it can only intersect the y- axis at one place and that is at -2.
Hope this helps
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