Could anyone please help me with this? I will vote brainliest
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N = number of compounding periods
Years = log (total / principal) / n * log (1 + rate / n)
Years = log (750 / 500) / 4 * log (1 + .025/n)
Years = log (1.5) / 4 * log (1<span><span>.00625) </span>
</span> <span>Years = 0.17609125906 / 4 * 0.0027058933759
</span><span>Years = 0.17609125906 </span> / <span> <span> <span> 0.0108235735 </span> </span> </span>
Years = <span> <span> <span> 16.2692348382 </span> </span> </span>
Source Calculator
http://www.1728.org/compint.htm
Years = log (total / principal) / n * log (1 + rate / n)
Years = log (750 / 500) / 4 * log (1 + .025/n)
Years = log (1.5) / 4 * log (1<span><span>.00625) </span>
</span> <span>Years = 0.17609125906 / 4 * 0.0027058933759
</span><span>Years = 0.17609125906 </span> / <span> <span> <span> 0.0108235735 </span> </span> </span>
Years = <span> <span> <span> 16.2692348382 </span> </span> </span>
Source Calculator
http://www.1728.org/compint.htm
The equation of a circle with center at (a, b) and radius, r, is given by
The given circle in the graph has the center at (0, 2) with the radius of 1 units.
<span>A circle with the same center as the circle in the graph and that passes through a point 2 units away from the given circle has its center at (0, 2) and a radius of 3 units.
Thus the equation of the circle is given by
</span>
The given circle in the graph has the center at (0, 2) with the radius of 1 units.
<span>A circle with the same center as the circle in the graph and that passes through a point 2 units away from the given circle has its center at (0, 2) and a radius of 3 units.
Thus the equation of the circle is given by