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3 years ago

Can you vive me please equivalent fraccions of 14/80 6/18 80/100 Please

Mathematics

2 answers:

-BARSIC- [3]3 years ago

8 0

14/80 = 7/40
6/18 = 1/3
80/100 = 4/5

suter [353]3 years ago

7 0

14/80 = 7/40
6/18 = 1/3
80/100 = 4/5

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The base of a triangle is 8 1 3 meters and the height of the triangle is the fourth root of 16 meters meters. What is the area o

just olya [345]

Answer:

The area of triangle is $8 \frac{1}{3}\ m^{2}$

Step-by-step explanation:

we know that

The area of a triangle is equal to

A=(1/2)bh

we have

b=8 1/3 m

convert to an improper fraction

8 1/3 m=(8*3+1)/3=25/3 m

The fourth root of 16 is equal to 2

$\sqrt[4]{16}=(2^{4})^{1/4}=2$

h=2 m

substitute

$A=(1/2)(25/3)2=25/3\ m^{2}$

convert to mixed number

$25/3=(24/3)+(1/3)=8+1/3=8 \frac{1}{3}\ m^{2}$

5 0

3 years ago

Ann's watch runs 2 minutes per hour too slow. Beth's watch runs 1 minute per hour too fast. For example, if both watches were co

Elenna [48]

Answer:

8 am Monday

Step-by-step explanation:

The difference between the two watches is 2+1= 3 minutes.

It would take 60/3 = 20 hours to have a difference of 60 minutes.

From noon Sunday it would be more 20 hours the earliest time there would be a difference of one hour between the two watches' time.

12 noon + 20 hours= 8 am Monday

7 0

3 years ago

A line passes through the point (4. 8) and has a slope of

valentina_108 [34]

Answer:

y=5x-12

Step-by-step explanation:

use equation y=mx+b

8=5(4)+b

8=20+b

-20 -20

-12=b

Final equation:

y=5x-12

6 0

2 years ago

Question 2 of 5

AlekseyPX

Given:

The different recursive formulae.

To find:

The explicit formulae for the given recursive formulae.

Solution:

The recursive formula of an arithmetic sequence is $f(n)=f(n-1)+d, f(1)=a,n\geq 2$ and the explicit formula is $f(n)=a+(n-1)d$ , where a is the first term and d is the common difference.

The recursive formula of a geometric sequence is $f(n)=rf(n-1), f(1)=a,n\geq 2$ and the explicit formula is $f(n)=ar^{n-1}$ , where a is the first term and r is the common ratio.

The first recursive formula is:

$f(1)=5$

$f(n)=f(n-1)+5$ for $n\geq 2$ .

It is the recursive formula of an arithmetic sequence with first term 5 and common difference 5. So, the explicit formula for this recursive formula is:

$f(n)=5+(n-1)(5)$

$f(n)=5+5(n-1)$

Therefore, the correct option is A, i.e., $f(n)=5+5(n-1)$ .

The second recursive formula is:

$f(1)=5$

$f(n)=3f(n-1)$ for $n\geq 2$ .

It is the recursive formula of a geometric sequence with first term 5 and common ratio 3. So, the explicit formula for this recursive formula is:

$f(n)=5(3)^{n-1}$

Therefore, the correct option is F, i.e., $f(n)=5(3)^{n-1}$ .

The third recursive formula is:

$f(1)=5$

$f(n)=f(n-1)+3$ for $n\geq 2$ .

It is the recursive formula of an arithmetic sequence with first term 5 and common difference 3. So, the explicit formula for this recursive formula is:

$f(n)=5+(n-1)(3)$

$f(n)=5+3(n-1)$

Therefore, the correct option is D, i.e., $f(n)=5+3(n-1)$ .

6 0

3 years ago

Read 2 more answers

Compute <br><br> I need help

nataly862011 [7]

$(\sqrt{3}-\sqrt{6}+\sqrt{12}-\sqrt{24})\times \frac{\sqrt{6}}{2} \\ (\sqrt{3}-\sqrt{6}+2\sqrt{3}-\sqrt{24})\times \frac{\sqrt{6}}{2} \\ (\sqrt{3}-\sqrt{6}+2\sqrt{3}-2\sqrt{6})\times \frac{\sqrt{6}}{2} \\ ((\sqrt{3}+2\sqrt{3})+(-\sqrt{6}-2\sqrt{6}))\times \frac{\sqrt{6}}{2} \\ (3\sqrt{3}-3\sqrt{6})\times \frac{\sqrt{6}}{2} \\ \frac{(3\sqrt{3}-3\sqrt{6})\sqrt{6}}{2} \\ \frac{3(\sqrt{3}-\sqrt{6})\sqrt{6}}{2}$

7 0

3 years ago