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slamgirl [31]
3 years ago
8

Please Help With all 3! Will Give 100 Points + Brainliest!

Mathematics
1 answer:
koban [17]3 years ago
3 0

Answer: I don't see anything. Maybe upload some images?

Step-by-step explanation:

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in the 9th grade, 7 of every 10 students is a girl. if there are 200 students in the 9th grade, how many of the students are gir
zubka84 [21]

Ratio of girls = 7/10

So, no. of girls = 200 × 7/10 = 20×7 = 140

4 0
3 years ago
Read 2 more answers
Calculus hw, need help asap with steps.
nikdorinn [45]

Answers are in bold

S1 = 1

S2 = 0.5

S3 = 0.6667

S4 = 0.625

S5 = 0.6333

=========================================================

Explanation:

Let f(n) = \frac{(-1)^{n+1}}{n!}

The summation given to us represents the following

\displaystyle \sum_{n=1}^{\infty} \frac{(-1)^{n+1}}{n!}=\sum_{n=1}^{\infty} f(n)\\\\\\\displaystyle \sum_{n=1}^{\infty} \frac{(-1)^{n+1}}{n!}=f(1) + f(2)+f(3)+\ldots\\\\

There are infinitely many terms to be added.

-------------------

The partial sums only care about adding a finite amount of terms.

The partial sum S_1 is the sum of the first term and nothing else. Technically it's not really a sum because it doesn't have any other thing to add to. So we simply say S_1 = f(1) = 1

I'm skipping the steps to compute f(1) since you already have done so.

-------------------

The second partial sum is when things get a bit more interesting.

We add the first two terms.

S_2 = f(1)+f(2)\\\\S_2 = 1+(-\frac{1}{2})\\\\S_2 = \frac{1}{2}\\\\S_2 = 0.5\\\\\\

The scratch work for computing f(2) is shown in the diagram below.

-------------------

We do the same type of steps for the third partial sum.

S_3 = f(1)+f(2)+f(3)\\\\S_3 = 1+(-\frac{1}{2})+\frac{1}{6}\\\\S_3 = \frac{2}{3}\\\\S_3 \approx 0.6667\\\\\\

The scratch work for computing f(3) is shown in the diagram below.

-------------------

Now add the first four terms to get the fourth partial sum.

S_4 = f(1)+f(2)+f(3)+f(4)\\\\S_4 = 1+(-\frac{1}{2})+\frac{1}{6}-\frac{1}{24}\\\\S_4 = \frac{5}{8}\\\\S_4 \approx 0.625\\\\\\

As before, the scratch work for f(4) is shown below.

I'm sure you can notice by now, but the partial sums are recursive. Each new partial sum builds upon what is already added up so far.

This means something like S_3 = S_2 + f(3) and S_4 = S_3 + f(4)

In general, S_{n+1} = S_{n} + f(n+1) so you don't have to add up all the first n terms. Simply add the last term to the previous partial sum.

-------------------

Let's use that recursive trick to find S_5

S_5 = [f(1)+f(2)+f(3)+f(4)]+f(5)\\\\S_5 = S_4 + f(5)\\\\S_5 = \frac{5}{8} + \frac{1}{120}\\\\S_5 = \frac{19}{30}\\\\S_5 \approx 0.6333

The scratch work for f(5) is shown below.

7 0
3 years ago
HELP PLEASE
Jet001 [13]

Answer:

c $11,751

Step-by-step explanation:

The function that models Alicia's car is

f(x) = 21000(0.93)^{x}

where x represents the number of years since she purchased the car.

We want to find the value of Alicia's car after 8 years.

We substitute x=8 into the formula to get:

f(8) = 21000(0.93)^{8}

f(8) = 21000(0.5596)

f(8) = 11751.218

We round to the nearest dollar to get:

f(8) =11751

The correct answer is C.

5 0
3 years ago
Which point satisfies the inquality 2×+y > 10 a. (2,3) b.(3,4) c. (3,2) d. (4,3)
Anna11 [10]
D. (4,3) that's the answer
8 0
4 years ago
Can somebody tell me how to solve these kind of problems?
Ugo [173]

Answer: 918km^2

Step-by-step explanation:

area(a): 1700km^2\\percentage(p): 5.75 = \frac{5.75}{100}=0.0575\\years(y): 8

Let x be the new dimension of the area;

x=a-(a*p*y)

x=(1700km^2)-(1700km^2*0.0575*8)\\x=1700km^2-782km^2\\x=918km^2

6 0
3 years ago
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