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slamgirl [31]
2 years ago
8

Please Help With all 3! Will Give 100 Points + Brainliest!

Mathematics
1 answer:
koban [17]2 years ago
3 0

Answer: I don't see anything. Maybe upload some images?

Step-by-step explanation:

You might be interested in
The LCD of theses fractions? <br> y/x + y/3+ y+1/y<br><br> Answers:<br> 3x+y<br> x+3+y<br> 3x+y
Dahasolnce [82]
3xy 

<span>y(3y)/3xy + y(xy)/3xy + (y+1)(3x)/3xy </span>

<span>NOW since all of the fractions have a denominator of 3xy, drop the denominators and solve using the numerators. </span>

<span>y(3y) + y(xy) + (y+1)(3x) </span>

<span>3y^2 + xy^2 + 3xy +3x </span>

<span>cannot simplify further.</span>
5 0
3 years ago
Rearrange the equation so r is the independent variable.<br><br> 10q - 5r = 30
Murljashka [212]

Answer:

q = 3 + 1/2r

Step-by-step explanation:

10q - 5r = 30

We want to solve for q

Add 5r to each side

10q - 5r+5r = 30+5r

10q = 30+5r

Divide by 10

10q/10 = 30/10 +5r/10

q = 3 + 1/2r

3 0
3 years ago
A pond forms as water collects in a conical depression of radius a and depth h. Suppose that water flows in at a constant rate k
Scrat [10]

Answer:

a. dV/dt = K - ∝π(3a/πh)^⅔V^⅔

b. V = (hk^3/2)/[(∝^3/2.π^½.(3a))]

The small deviations from the equilibrium gives approximately the same solution, so the equilibrium is stable.

c. πa² ≥ k/∝

Step-by-step explanation:

a.

The rate of volume of water in the pond is calculated by

The rate of water entering - The rate of water leaving the pond.

Given

k = Rate of Water flows in

The surface of the pond and that's where evaporation occurs.

The area of a circle is πr² with ∝ as the coefficient of evaporation.

Rate of volume of water in pond with time = k - ∝πr²

dV/dt = k - ∝πr² ----- equation 1

The volume of the conical pond is calculated by πr²L/3

Where L = height of the cone

L = hr/a where h is the height of water in the pond

So, V = πr²(hr/a)/3

V = πr³h/3a ------ Make r the subject of formula

3aV = πr³h

r³ = 3aV/πh

r = ∛(3aV/πh)

Substitute ∛(3aV/πh) for r in equation 1

dV/dt = k - ∝π(∛(3aV/πh))²

dV/dt = k - ∝π((3aV/πh)^⅓)²

dV/dt = K - ∝π(3aV/πh)^⅔

dV/dt = K - ∝π(3a/πh)^⅔V^⅔

b. Equilibrium depth of water

The equilibrium depth of water is when the differential equation is 0

i.e. dV/dt = K - ∝π(3a/πh)^⅔V^⅔ = 0

k - ∝π(3a/πh)^⅔V^⅔ = 0

∝π(3a/πh)^⅔V^⅔ = k ------ make V the subject of formula

V^⅔ = k/∝π(3a/πh)^⅔ -------- find the 3/2th root of both sides

V^(⅔ * 3/2) = k^3/2 / [∝π(3a/πh)^⅔]^3/2

V = (k^3/2)/[(∝π.π^-⅔(3a/h)^⅔)]^3/2

V = (k^3/2)/[(∝π^⅓(3a/h)^⅔)]^3/2

V = (k^3/2)/[(∝^3/2.π^½.(3a/h))]

V = (hk^3/2)/[(∝^3/2.π^½.(3a))]

The small deviations from the equilibrium gives approximately the same solution, so the equilibrium is stable.

c. Condition that must be satisfied

If we continue adding water to the pond after the rate of water flow becomes 0, the pond will overflow.

i.e. dV/dt = k - ∝πr² but r = a and the rate is now ≤ 0.

So, we have

k - ∝πa² ≤ 0 ---- subtract k from both w

- ∝πa² ≤ -k divide both sides by - ∝

πa² ≥ k/∝

5 0
3 years ago
Plz help will be marked BRAINLIEST! <br> Thanks
blagie [28]

Answer:

a) a + c = 90

d) a + b + c + 30 = 180

e) The angles marked a and b are vertical

f) The angles marked a and c are complementary.

Step-by-step explanation:

A complementary angle is and angle that has a sum of 90 degrees. A vertical angle is 2 angles facing each other, that are completely identical. 180 degrees is the sum of a strait line. 90 degrees is a right angle.

Hope this helps! Have a wonderful rest of your day!

<em>-kiniwih426</em>

6 0
3 years ago
Read 2 more answers
ASAP need help please
Akimi4 [234]

Answer:

A or B

Step-by-step explanation:

5 0
3 years ago
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