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Svetradugi [14.3K]
2 years ago
14

Can someone please help me

Mathematics
1 answer:
WITCHER [35]2 years ago
4 0

Answer:

if I am correct the answer should be 2

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I really need help please
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Does the relation {(-2,2), (-7,1), (-3,9), (-8,4), (-9,5), (-6,8)) represent
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2 years ago
If 28% of students in College are near-sighted, the probability that in a randomly chosen group of 20 College students, exactly
cluponka [151]

Answer: (D) 16%

Step-by-step explanation:

Binomial probability formula :-

P(x)=^nC_xp^x(1-p)^n-x, where n is the sample size , p is population proportion and P(x) is the probability of getting success in x trial.

Given : The proportion of students in College are near-sighted : p= 0.28

Sample size : n= 20

Then, the the probability that in a randomly chosen group of 20 College students, exactly 4 are near-sighted is given by :_

P(x=4)=^{20}C_4(0.28)^4(1-0.28)^{20-4}\\\\=\dfrac{20!}{4!16!}(0.28)^4(0.72)^{16}\\\\=0.155326604912\approx0.16\%

Hence, the probability that in a randomly chosen group of 20 College students, exactly 4 are near-sighted is closest to 16%.

7 0
3 years ago
Complete the table below for the function y = -6x + 4.
liraira [26]
When x= -5, y= 34; when y= 64, x = -10
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