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givi [52]
3 years ago
10

Which place value do you use to compare 437,812 and 432,729?

Mathematics
1 answer:
dusya [7]3 years ago
8 0

Answer: the hundreds place

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Help please help me please​
madam [21]

Answer:

B

Step-by-step explanation:

Only 1 because

1/1 = 1

2/1 = 2

The answer can't be 0 because we can't divide by zero.

The answer can't be 2 because you can't divide 1 by 2 without having a number with decimal places

Same thing for the 4

6 0
2 years ago
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6(x + 2) - x = 4(x + 4) + 7<br> x = 11
Simora [160]
That’s right they both equal 67
6 0
3 years ago
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Cathrine has £7000 to invest.
Anvisha [2.4K]
Since this is a compound interest problem, you have to take note that the amount Catherine will get per year is not the same. It will increase per year since it is compounded. So first, we get the amount after one year. This will be 7000 x 0.04 which is 280 plus 7280. In the second year, she will get 7571 (7280 x 0.04 + 7280). In the third year, she will get 7874 (7571 x 0.04 + 7571). In the fourth year, she will get 8189 (7874 x 0.04 + 7874). And finally in the fifth year, she will get 8517 (8189 x 0.04 +8189). So after five years, she has 8517
4 0
3 years ago
What elements, found on the right side of the periodic table, usually accept electrons and have a negative valence? A. metals B.
krek1111 [17]
<h2>ANSWER:</h2><h3>Non Elements</h3><h3 /><h2>NOTES:</h2><h3>With the exception of HYDROGEN, the elements on the left side of the periodic table are METALS. Elements on the right side of the periodic table are NONMETALS.</h3>
5 0
2 years ago
If Whitney wrote the decimal representations for the first 300 positive integer multiples of 5 and did not write any other numbe
fiasKO [112]

Answer:

201 times

Step-by-step explanation:

Since it's the first 300 positive integer multiples of 5, then the last integer will be: 300 × 5 = 1500

While the first is 5.

The sequence is like this;

5, 10, 15, 20, 25, 30, 35, .. 1500

Since for every 2 integers that are multiples of 5, 1 will include the digit 5, then it means that, number of times the unit place will have 5 is; 300/5 = 150 times

Now, between 5 and 100, the only value that has 5 in it's tense place is 50 & 55.

So for every 100 numbers, we have 2 times to write 5 in the tens place. Thus, for 1500 numbers, we will write 5 in the tens place: 1500/100 × 2 = 30 times

Now, for the hundreds place, from 500 and 600, we have 21 multiples of 5 inclusive of 500 and 600 but since we want the one that has 5 in the hundreds place, then it is 20 as they all start with 5 excluding 600.

Also, from 1000 to 1500, the only number that has 5 in its hundreds place is 1500.

Thus,total times 5 is written in the hundreds place = 21 times

Total number of times 5 is written = 150 + 30 + 21 = 201 times

5 0
2 years ago
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