The angles in a triangle are such that one angle is 128 more than the smallest angle, while the third angle is 2 times as large
as the smallest angle. Find the measures of all three angles.
2 answers:
■ Answer:
a = 141°
b = 13°
c = 26°
■ Step-by-step explanation:
a = 128 + b
c = 2b
a + b + c = 128
replace a & c
(128 + b) + b + 2b = 180
4b = 180 - 128
4b = 52
b = 13°
a = 128° + 13° = 141°
c = 2×13° = 26°
We can write an equation using the information given in the problem.
2x + x + x + 128 = 180
Solve for x.
4x + 128 = 180
4x = 52
x = 13
Second angle:
13 + 128 = 141
Third angle:
13 * 2 = 26
Therefore, the answer is [ 13, 26, and 141 ]
Best of Luck!
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Answer:
x =76.45 degrees
Step-by-step explanation:
72 + 252 – 2(7)(25)cos _x__=242
combine like terms
324-350cosx = 242
subtract 324 from each side
-350x = -82
divide by -350
cos x = -82/-350
cos x = 82/350
take the arccos of each side
arccos (cos x) = arccos (82/350)
x =76.45 degrees
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1)Alternate exterior
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