Question

To get to his office from home, Greg walks 6 blocks north and then 3 blocks east. After work he meets some friends at a cafe; to get there he walks 3 blocks south and 7 blocks west. All blocks are 660 feet long. What is the straight-line distance from the cafe to his home?

Answer 1

Answer:

total distance  = 3300 ft

Step-by-step explanation:

we know here displacement S is  in vector form that is

$\vec{S} = \vec{S1} +\vec{S2}+\vec{S3}+\vec{S4}$   ......................1

$\vec{S} = (3\hat{i}+6\hat{j}) + (-7\hat{i}-3\hat{j})$

and

$\vec{S} =(-4\hat{i}+3\hat{j})$

and

magnitude is

$\left| \vec{S} \right| = \sqrt{(-4)^2+3^2}$

$\left| \vec{S} \right| = \sqrt{25}$

$\left| \vec{S} \right| = 5$

so here distance from home to cafe is

S = 5 × 660

total distance  = 3300 ft