Question

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Answer 1

For this case we have the following system of equations:

$8x-9y = -122\\-8x-6y = -28$

To solve, we add both equations:

$8x-8x-9y-6y = -122-28\\-15y = -150\\y = \frac {-150} {- 15}\\y = 10$

We find the value of "x":

$8x = -122 + 9y\\x = \frac {-122 + 9y} {8}\\x = \frac {-122 + 9 (10)} {8}\\x = \frac {-122 + 90} {8}\\x = \frac {-32} {8}\\x = -4$

The solution is (-4,10)

ANswer:

Option C