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gtnhenbr [62]
3 years ago
14

What is the value of x? 3 4 6 8

Mathematics
2 answers:
bekas [8.4K]3 years ago
8 0
The longer sides of the rectangles should be the same value, so we can make the lower part of the equation equal to 18, which is 4.
We can even find the y value by making it equal to 10, which is 3.
Bess [88]3 years ago
6 0

Answer:

 x=4 that is Option 2 is correct.

Step-by-step explanation:

The given figure is rectangle and since the opposite sides of rectangle are equal

hence, 18=10+2x

After simplification so as to get the value of x we get:

18-10 =2x

8=2x

After further simplification we get:

x=4

Therefore, option 2 is correct.

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450.4

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Please help pleaseeeee
Rudik [331]

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B 1/2

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3 0
3 years ago
Factor completely x^8- 16.
Nataly_w [17]

Answer:

Step-by-step explanation:


So in this example we'll be using the difference of squares which essentially states that: (a-b)(a+b)=a^2-b^2 or another way to think of it would be: a-b=(\sqrt{a}-\sqrt{b})(\sqrt{a}+\sqrt{b}). So in this example you'll notice both terms are perfect squares. in fact x^n is a perfect square as long as n is even. This is because if it's even it can be split into two groups evenly for example, in this case we have x^8. so the square root is x^4 because you can split this up into (x * x * x * x) * (x * x * x * x) = x^8. Two groups with equal value multiplying to get x^8, that's what the square root is. So using these we can rewrite the equation as:

x^8-16 = (x^4-4)(x^4+4)

Now in this case you'll notice the degree is still even (it's 4) and the 4 is also a perfect square, and it's a difference of squares in one of the factors, so it can further be rewritten:

x^4-4 = (x^2-2)(x^2+2)

So completely factored form is: (x^2-2)(x^2+4)(x^4+4)

I'm assuming that's considered completely factored but you can technically factor it further. While the identity difference of squares technically only applies to difference of squares, it can also be used on the sum of squares, but you need to use imaginary numbers. Because x^2+4 = x^2-(-4). and in this case a=x^2 and b=-4. So rewriting it as the difference of squares becomes: x^4+4 = x^4 - (-4) = (x^2-\sqrt{-4})(x^2+\sqrt{-4}) = (x^2-2i)(x^2+2i) just something that might be useful in some cases.

7 0
1 year ago
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