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Aleonysh [2.5K]
3 years ago
8

Please solve both. help quickly!!

Mathematics
2 answers:
WINSTONCH [101]3 years ago
7 0

Answer:

0.1% = 10    1%=1/100

Nata [24]3 years ago
6 0

Answer:

1/1000 for the 1st

1/100 for the 2nd

Step-by-step explanation:

0.1% is 0.001, which is 1/1000

1% is 0.01, which is 1/100

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Can someone help me?​
Tju [1.3M]

Answer:

B

Step-by-step explanation:

in table B if x = 1     y cannot equal both 1 and -1

    no function can have x equal to two or more unique y's

   

7 0
3 years ago
Olivia has blue, pink and orange counters in a bag.
Keith_Richards [23]
Blue= 4
Orange=2
Hope this helped you! :)

————————————————————-
5 0
3 years ago
Read 2 more answers
I need to solve this in system of equations form
aksik [14]

Is this even answerable, because u would need to figure out what ‘b’ is to figure out the answer

3 0
3 years ago
The owner of a music store gathered data from several schools about the number of students in their concert and marching bands.
crimeas [40]

Answer:

25 students

Step-by-step explanation:

What we need to do here is to do some tracing. We simply need to go to the point on the concert band where we have the value 35.

After sighting this value, we then make a tracing to the line of best fit. Then from this line of best fit, we trace the point on the matching band that correlated with the value 35.

If properly traced, we would arrive at a value of 25 on the marching band

6 0
3 years ago
In what follows use any of the following tests: Regression, multiple regression, one-sided t-test, or two-sided t-test. All conc
Yakvenalex [24]

Answer:

  1. Two sided  t-test ( d )
  2.  0.245782  ( c )
  3. Since P-value is too large we cannot conclude that the students’ weight are different for these two schools. ( c )
  4. The test is inconclusive; thus we cannot claim that the average weights are different. ( b )

Step-by-step explanation:

1)  Test performed is a Two sided test and this because we are trying to determine the mean difference between two groups irrespective of their direction

<u>2) Determine the P-value ( we will use a data-data analysis approach on excel data sheet while assuming Unequal variances )</u>

                               yes             No

Mean                   94.47059   89.76471

Variance              173.2647     95.19118

Observations            17            17

df                               30

t Stat                       1.184211  

P(T<=t) one-tail 0.122814  

t Critical one-tail 1.697261

P(T<=t) two-tail        0.245782

Hence The p-value =  0.245782

3) Since P-value is too large we cannot conclude that the students’ weight are different for these two schools.

4)   The test is inconclusive; thus we cannot claim that the average weights are different.

8 0
3 years ago
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