s = standard version amount
h = high quality version amount
we know that there were 1090 downloads of the song, meaning s + h = 1090.
we also know that the total amount of MBs downloaded was 3353 MBs, and since the standard is 2.1 MBs and the high quality is 4.9MBs, then 2.1s + 4.9h = 3353.
![\begin{cases} s+h=1090\\ 2.1s + 4.9h = 3353\\[-0.5em] \hrulefill\\ h = 1090 - s \end{cases}\qquad \stackrel{\textit{substituting on the 2nd equation}}{2.1s+4.9(1090-s) = 3353} \\\\\\ 2.1s + 5341 - 4.9s = 3353\implies -2.8s + 5341 = 3353 \\\\\\ -2.8s=-1988\implies s = \cfrac{-1988}{-2.8}\implies \boxed{s = 710}](https://tex.z-dn.net/?f=%5Cbegin%7Bcases%7D%20s%2Bh%3D1090%5C%5C%202.1s%20%2B%204.9h%20%3D%203353%5C%5C%5B-0.5em%5D%20%5Chrulefill%5C%5C%20h%20%3D%201090%20-%20s%20%5Cend%7Bcases%7D%5Cqquad%20%5Cstackrel%7B%5Ctextit%7Bsubstituting%20on%20the%202nd%20equation%7D%7D%7B2.1s%2B4.9%281090-s%29%20%3D%203353%7D%20%5C%5C%5C%5C%5C%5C%202.1s%20%2B%205341%20-%204.9s%20%3D%203353%5Cimplies%20-2.8s%20%2B%205341%20%3D%203353%20%5C%5C%5C%5C%5C%5C%20-2.8s%3D-1988%5Cimplies%20s%20%3D%20%5Ccfrac%7B-1988%7D%7B-2.8%7D%5Cimplies%20%5Cboxed%7Bs%20%3D%20710%7D)
Using the discrete distribution, it is found that the probability that it offers an even number of honors classes is of 0.68.
<h3>What is the discrete probability distribution?</h3>
The distribution for the number of honors classes the school offers is given by:
Hence the probability of an even number is given by:
P(even) = P(X = 0) + P(X = 2) + P(X = 4) = 0.38 + 0.25 + 0.05 = 0.68.
More can be learned about discrete probability distributions at brainly.com/question/24802582
#SPJ1
Answer:
(x+4)(x-4)
Step-by-step explanation:
Here is a simple help for when you can take a square root of both terms:
(x+(squareroot)) x (x-(squareroot))
x times x = x^2
4 x -4 = -16
This is just a learned skill, most often from Alg 2, Alg 2 w/ trig, and Precal!
Hope this helps!
Answer:
x= 3, -4
Step-by-step explanation:
