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Nonamiya [84]
3 years ago
13

Help it’s urgent please

Mathematics
1 answer:
Anon25 [30]3 years ago
8 0

Answer:

\frac{5 {x}^{2}  + 20xy + 20 {y}^{2} }{x ^{2} - xy -  {6y}^{2}  }

To simplify first factorize both the numerator and the denominator

For the numerator

5x² + 20xy + 20y²

Factor 5 out

5 ( x² + 4xy + 4y²)

Using a² + 2ab + b² = ( a + b)²

The numerator is

5( x + 2y)²

For the denominator

x² - xy - 6y²

Rewrite -xy as a difference

x² + 2xy - 3xy - 6y²

Factorize

We have the denominator as

( x + 2y)( x - 3y)

So we now have

<h2>\frac{5(x + 2y)(x + 2y)}{(x + 2y)(x - 3y)}</h2>

Simplify

<h2>\frac{5(x + 2y)}{x - 3y}</h2>

We have the final answer as

<h2>\frac{5x + 10y}{x - 3y}</h2>

Hope this helps you

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Six sophomores and 14 freshmen are competing for two alternate positions on the debate team. Which expression represents the pro
Elanso [62]

Answer:

<em>Choose the first alternative</em>

\displaystyle P=\frac{_{1}^{6}\textrm{C}\ _{1}^{5}\textrm{C}}{_{2}^{20}\textrm{C}}

Step-by-step explanation:

<u>Probabilities</u>

The requested probability can be computed as the ratio between the number of ways to choose two sophomores in alternate positions (N_s) and the total number of possible choices (N_t), i.e.

\displaystyle P=\frac{N_s}{N_t}

There are 6 sophomores and 14 freshmen to choose from each separate set. There are 20 students in total

We'll assume the positions of the selections are NOT significative, i.e. student A/student B is the same as student B/student A.

To choose 2 sophomores out of the 6 available, the first position has 6 elements to choose from, the second has now only 5

_{1}^{6}\textrm{C}\ _{1}^{5}\textrm{C} \text{ ways to do it}

The total number of possible choices is

_{2}^{20}\textrm{C} \text{ ways to do it}

The probability is then

\boxed{\displaystyle P=\frac{_{1}^{6}\textrm{C}\ _{1}^{5}\textrm{C}}{_{2}^{20}\textrm{C}}}

Choose the first alternative

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