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lilavasa [31]
3 years ago
14

Ariana buys an ant farm from a store near her home. the ant farm price $12, and the sales tax is 7% what is the total price of t

he ant farm
Mathematics
1 answer:
aalyn [17]3 years ago
6 0

Answer:

The total price for ant farm is $12.84

Step-by-step explanation:

The price of ant farm =  $ 12

The sales tax on the  price = 7%

Noe, 7% of $12 = \frac{7}{100} \times 12 = 0.84

⇒The tax amount on the price = $0.84

So, the Taxed amount = The original price  + Tax

$ 12 + $0.84  = $12.84

Hence the total price for ant farm is $12.84

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Y=5/2x-19 and 5x+2y=-8 a perpendicular,parallel or intersecting lines?
dimaraw [331]

Answer:

There intersecting lines

Step-by-step explanation:

5x+2y=-8

-5x            -5x

2y=-8 -5x

/2   /2  /2

y=-4 -5/2x also

y=-5/2x - 4

&

y=5/2x - 19

neither parallel (slope is not the same)

or perpendicular (slope is not reciprocal or opposite signed)

hope i helped

6 0
4 years ago
Rewrite the equation 2x + 6y = 7 in slope-intercept form.
4vir4ik [10]
Answer: y = -2x + 1 1/6

Steps:
2x + 6y = 7
2x + y = 7/6
y = 7/6
y = -2x + 7/6
y = -2x + 1 1/6
4 0
3 years ago
Read 2 more answers
Given: <br> PQ<br> ⊥<br> QR<br> , PR=20,<br> SR=11, QS=5<br> Find: The value of PS.
dlinn [17]

Answer:

The value of the side PS is 26 approx.

Step-by-step explanation:

In this question we have two right triangles. Triangle PQR and Triangle PQS.

Where S is some point on the line segment QR.

Given:

PR = 20

SR = 11

QS = 5

We know that QR = QS + SR

QR = 11 + 5

QR = 16

Now triangle PQR has one unknown side PQ which in its base.

Finding PQ:

Using Pythagoras theorem for the right angled triangle PQR.

PR² = PQ² + QR²

PQ = √(PR² - QR²)

PQ = √(20²+16²)

PQ = √656

PQ = 4√41

Now for right angled triangle PQS, PS is unknown which is actually the hypotenuse of the right angled triangle.

Finding PS:

Using Pythagoras theorem, we have:

PS² = PQ² + QS²

PS² = 656 + 25

PS² = 681

PS = 26.09

PS = 26

7 0
3 years ago
Select Translation, Reflection, or Rotation to identify the single transformation that transforms ∆PQR to ∆P'Q'R'.
Sergeeva-Olga [200]

Part A

Represents 'Reflection'. This is so because the y-coordinates of P, Q and R remain the same in P' , Q' and R', and only the x-coordinate changes. Hence, it is reflection along the y-axis

Part B

Represents 'Rotation'. Here, the x-coordinates and y-coordinates of each of the points have changed, and the figure has been rotated clockwise around the point Q by 90°

Part C

Represents a combination of 'Translation' and 'Reflection'. Here either of the two has happened:

  • First, all the points have been moved downwards by a fixed distance, thus changing the y-coordinate. Then, the resulting image has been reflected along the y-axis, thus changing the x-coordinate of all the points
  • First, all the points have been moved to the right by a fixed distance, thus changing the x-coordinate. Then, the resulting image has been reflected along the x-axis, thus changing the y-coordinate of all the points

Part D

Represents 2 'Translations'. Here the image has been shifted by a fixed distance in both the downward direction and the right direction. Thus, it has resulted in change of both x and y coordinates.

8 0
4 years ago
I really need help quick I’ve been working this out for 1 hour already
wolverine [178]

Answer:

B

Step-by-step explanation:

Hope this helps

4 0
3 years ago
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