Answer:
D. The horizontal cross-sections of the prisms at the same height must have the same area.
Step-by-step explanation: I dont know what the guy above is saying but this is the right answer
Answer:
Step-by-step explanation:
y= -4x² - 16x - 14
Take the coefficient of x² as the common factor
y = - 4(x² + 4x + 7/2)
Add (b/2)² to complete the square
y = - 4( x² + 4x + 2² - 2² + 7/2)
Complete the square
y = -4( (x + 2)² - 1/2)
Remove the bracket
y = -4(x + 2)² + 2
Answer: y = -4(x + 2)² + 2
So basically what you wanna do is multiply across giving you 40/88 which you can simplify down to 5/11
Hope this helps :D
Lateral Area means Area of all four triangles
Now area of 1 triangle = ![\frac{\sqrt{3}}{4} a^2 = \frac{\sqrt{3}}{4} 8^2](https://tex.z-dn.net/?f=%20%5Cfrac%7B%5Csqrt%7B3%7D%7D%7B4%7D%20a%5E2%20%20%3D%20%20%5Cfrac%7B%5Csqrt%7B3%7D%7D%7B4%7D%208%5E2%20)
=
square meters
Now for four triangles we multiply by 4
So
Lateral area of pyramid =
m^2
that is Option D