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3 years ago

Prove the circles are similar :).

Mathematics

1 answer:

Fudgin [204]3 years ago

5 0

Answer:

Translate circle C 3 units towards the right and 5 units up.

Dilate this translated circle C by a factor 2.5. It will overlap (become congruent to) circle A

This is enough to prove that the two circles are similar

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Anusha is walking on a hiking trail at a rate of Three-fourths miles in One-fourth hour. At this rate, how far will Anusha walk

grandymaker [24]

Answer:

Step-by-step explanation:

3/4 + 3/4 + 3/4 + 3/4 = 12/4 = 3. She will walk 3 miles in an hour.

6 0

3 years ago

1.)12.5+(-31.5)=<br>2.)-31.91+(-16.7)=<br>3.)1/6+(-11/12)+2/3=<br>4.)29+(-15.7)+(-31.05)=

Xelga [282]

1. = Step 1. Simplify Brackets and you get $12.5 - 31.5$ Step 2. Simplify and you get $-19
$ which is your answer.

2. = Step 1. Simplify Brackets and you get $-31.91-16.7$ Step 2. Simplify and you get $-48.61$

3. = Step 1. Simplify Brackets and you get $\frac{1}{6} - \frac{11}{12} + \frac{2}{3}$ Step 2. Simplify and you get $- \frac{1}{12}$

4. Step 1. = Simplify Brackets and you get $29-15.7-31.05$ Step 2. Simplify and you get $-17.75$

5 0

3 years ago

Which property is demonstrated in the equation 0 x 35 = 0?

Kisachek [45]

Answer:

Step-by-step explanation:

the property of zero,

multiplication property of zero

8 0

3 years ago

4. Using the geometric sum formulas, evaluate each of the following sums and express your answer in Cartesian form.

nikitadnepr [17]

Answer:

$\sum_{n=0}^9cos(\frac{\pi n}{2})=1$

$\sum_{k=0}^{N-1}e^{\frac{i2\pi kk}{2}}=0$

$\sum_{n=0}^\infty (\frac{1}{2})^n cos(\frac{\pi n}{2})=\frac{1}{2}$

Step-by-step explanation:

$\sum_{n=0}^9cos(\frac{\pi n}{2})=\frac{1}{2}(\sum_{n=0}^9 (e^{\frac{i\pi n}{2}}+ e^{\frac{i\pi n}{2}}))$

$=\frac{1}{2}(\frac{1-e^{\frac{10i\pi}{2}}}{1-e^{\frac{i\pi}{2}}}+\frac{1-e^{-\frac{10i\pi}{2}}}{1-e^{-\frac{i\pi}{2}}})$

$=\frac{1}{2}(\frac{1+1}{1-i}+\frac{1+1}{1+i})=1$

2nd

$\sum_{k=0}^{N-1}e^{\frac{i2\pi kk}{2}}=\frac{1-e^{\frac{i2\pi N}{N}}}{1-e^{\frac{i2\pi}{N}}}$

$=\frac{1-1}{1-e^{\frac{i2\pi}{N}}}=0$

3th

$\sum_{n=0}^\infty (\frac{1}{2})^n cos(\frac{\pi n}{2})==\frac{1}{2}(\sum_{n=0}^\infty ((\frac{e^{\frac{i\pi n}{2}}}{2})^n+ (\frac{e^{-\frac{i\pi n}{2}}}{2})^n))$

$=\frac{1}{2}(\frac{1-0}{1-i}+\frac{1-0}{1+i})=\frac{1}{2}$

What we use?

We use that

$e^{i\pi n}=cos(\pi n)+i sin(\pi n)$

and

$\sum_{n=0}^k r^k=\frac{1-r^{k+1}}{1-r}$

6 0

3 years ago

Which equation represents each scenario

Mkey [24]

Answer:

if she question 1 spend $25 out of the $150, then you would do 150 sub 25 to get 125

Kevin has 10 signs. he's adding 5 signs, so divide 10 to 5 to get 2

Harvey has 5 in 1 minute, i would say in 2 minutes he'll have 10

Fran adds $25 to her $150 then she'll get $175.

Step-by-step explanation:

P= Parentheses

E= Exponent

M= Multiplication

D= Division

A= Addition

S= Subtraction

If this doesn't help then sorry , hope this helps.

4 0

2 years ago