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UNO [17]
3 years ago
7

Prove the circles are similar :).

Mathematics
1 answer:
Fudgin [204]3 years ago
5 0

Answer:

Translate circle C 3 units towards the right and 5 units up.

Dilate this translated circle C by a factor 2.5. It will overlap (become congruent to) circle A

This is enough to prove that the two circles are similar

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If there are 22 successes in a sample with a size of 40, what is the sample
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Answer:

A

Step-by-step explanation:

22 successes out of a group of 40 means 22/40 were good. Now, simplify 22/40. Both can be divided by 2.

22/2 = 11

40/2 = 20

Now you have 11/20. Put this in decimal form and you have 0.55

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3 years ago
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PLS HELP NO LINKS PLEASE I NEED ANSWER.What is the surface area of the following triangular prism? 126 yd 2 96 yd 2 162 yd 2 90
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Answer:

The answer is 96 yd 2

Step-by-step explanation:

5x7=35

4x7=28

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then you add all of the total values together:

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Today only, every sweatshirt is $4.25 less than normal price. Right now if you buy 5 sweatshirts, the total cost will be $106.25
Musya8 [376]

Answer:

Step-by-step explanation:

The normal price of the sweatshirt will be $21.50 because if you divide $78.75 by 5 you get $15.75 for each sweatshirt then you add the $5.75 with will make the original price $21.50

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What is the simplified version of 3\sqrt{135}
Aleonysh [2.5K]

Answer:

The simplified version of \sqrt[3]{135} is 3\sqrt[3]{5}.

Step-by-step explanation:

The given expression is

\sqrt[3]{135}

According to the property of radical expression.

\sqrt[n]{x}=(x)^{\frac{1}{n}}

Using this property we get

\sqrt[3]{135}=(135)^{\frac{1}{3}}

\sqrt[3]{135}=(27\times 5)^{\frac{1}{3}}

\sqrt[3]{135}=(3^3\times 5)^{\frac{1}{3}}

\sqrt[3]{135}=(3^3)^{\frac{1}{3}}\times (5)^{\frac{1}{3}}      [\because (ab)^x=a^xb^x]

\sqrt[3]{135}=3\times \sqrt[3]{5}     [\because \sqrt[n]{x}=(x)^{\frac{1}{n}}]

\sqrt[3]{135}=3\sqrt[3]{5}

Therefore the simplified version of \sqrt[3]{135} is 3\sqrt[3]{5}.

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3 years ago
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Elena L [17]

Answer:

p - a - c = b

Step-by-step explanation:

p = a + b + c

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p - a - c = a - a + b

+ c - c

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