Question

Suppose that the​ amount, in​ grams, of polonium 210 present in a given sample is determined by the function defined by ​A(t)equals401e Superscript negative 0.032 t​, where t is the time in years. Find the amount present in a sample of 401 grams after 25 years.

Answer 1

Answer:

The amount present in a sample of 401 grams after 25 years is $180\ g$

Step-by-step explanation:

we have

A(t) -----> the​ amount, in​ grams, of polonium 210 present in a given sample

t -----> the time in years

$A(t)=401e^{-0.032t}$

we know that

To find out the amount present in a sample of 401 grams after 25 years, substitute the value of t=25 years in the equation and solve for A(t)

For t=25 years

$A(25)=401e^{-0.032(25)}$

$A(25)=180.18\ g$