I believe if that says three minus four times three minus five or three plus negative four times three plus negative five (same thing) then the answers should be positive two (2.)
Answer:
Center (-13,11) , radius 3
Step-by-step explanation:
The given circle has equation

We compare this to the general equation.

where (-a,-b) is the center.
This implies that;
2a=26

2b=-22
b=-11
The center is therefore (-13,11)
The radius is given by



The radius is 3
Answer:
The combination 9 mm, 6mm, 5mm will not form a triangle.
9 +6 = 15 > 5
6+5= 11 < 9
9+5 =14 > 6
Explanation :
because the side length of triangle does not obey triangle inequality theorem.
The triangle inequality theorem:
The sum of the lengths of any two sides of a triangle is greater than the length of the third side.
Charge per day = $90 / 15 = $ 6
<span>Charge per year = $ 6 * 365 1/4 ( If the year contains 365 1/4 days) </span>
<span>= $ 2191.5 </span>
<span>As a percentage = 2191.5 / 1460 * 100 = 150 %
So the answer should be 150%</span>
<h3>
Answer:</h3>
C=52.08π
<h3>
Solution:</h3>
- Circumference of a circle:
- C=2πr
- where
- π=3.14...
- r= radius
- In this case, r is equivalent to 26.04 ft.
- C=2π×26.04
- Multiply:
- C=52.08π (in terms of pi)
Hope it helps.
Do comment if you have any query.