3 years ago

Given this equation, what is the largest possible value for z?

1 answer:

7 0

Hello,
z=-2x²+15x-3y²+21y-6
=-2(x²-2*15/2*x+(15/2)²) -3(y²-2*7/2y+(7/2)²)-6+2*225/4+3*49/4
=-2(x-15/2)²-3(y-7/2)²+573/4

The max is for x-15/2=0 and y-7/2=0 thus 537/4

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PSYCHO15rus [73]

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Step-by-step explanation:

NPQ is a triangle.

We know the sum of 3 angles of a triangle is 180 degrees. So we can write:

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Now, we can solve for x:

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