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marusya05 [52]
4 years ago
8

what is the approximate distance between the points (-5, 1) and (-2, 3) on a coordinate grid? A. 3.32 units B. 3.61 units C. 2.2

3 units D. 7.81 units
Mathematics
1 answer:
Allisa [31]4 years ago
4 0
By coordinate geometry
\sqrt{(-5-(-2))^2 + (1 - 3)^2} = \sqrt{13}
therefore the distance is 3.61units
please mark as brainliest
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<h2>Answer:</h2>

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____ [38]

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∠Q = 63.4º, PQ = 2, QO = 4.47

Step-by-step explanation:

A triangle is a polygon with three sides and three angles. There are different types of triangles such as the equilateral triangle, isosceles triangle, scalene triangle, right angled triangle.

Triangle POQ is a right angled triangle because ∠P = 90°. Also, ∠O = 26.6°.

Therefore in ΔPOQ: ∠P + ∠O + ∠Q = 180° (sum of angles in a triangle).

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We can find PQ and QO using sine rule. Sine rule for ΔPOQ is given as:

\frac{PO}{sin Q}= \frac{PQ}{sinO}= \frac{QO}{sin P}\\\\Finding\ PQ  :\\\\\frac{PO}{sin Q}= \frac{PQ}{sinO}\\\\\frac{4}{sin(63.4)} =\frac{PQ}{sin(26.6)}\\\\PQ= \frac{4}{sin(63.4)} *sin(26.6)\\\\PQ = 2\\\\Also\ finding\ QO:\\\\\frac{PO}{sin Q}= \frac{QO}{sinP}\\\\\frac{4}{sin(63.4)} =\frac{QO}{sin(90)}\\\\QO=\frac{4}{sin(63.4)} *sin(90)\\\\QO = 4.47

4 0
3 years ago
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