Question

A father is three times as old as his son . After fifteen years the father will be twice as old as his son's age at that time. Hence what will be the fathers present age ?

Answer 1

Let's solve this problem step-by-step.

STEP-BY-STEP EXPLANATION:

We will be using simultaneous equations to solve this problem.

Let's establish the two equations we will be using to solve the problem.

Let present age of father = f

Let present age of son = s

Equation No. 1 -

f = 3s

Equation No. 2 -

f + 15 = 2s

To begin with, we will substitute the value of ( f ) from the first equation into the second equation to solve for ( s ).

Equation No. 2 -

f + 15 = 2s

( 3s ) + 15 = 2s

3s - 2s = - 15

s = - 15

Next we will substitute the value of ( s ) from the second equation into the first equation to solve for ( f ).

Equation No. 1 -

f = 3s

f = 3 ( - 15 )

f = - 45

FINAL ANSWER:

Therefore, the present age of the father is - 45 years old.

It isn't possible for someone to be negative years old but this is the answer that I obtained from the equations.

Hope this helps! :)
Have a lovely day! <3