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muminat
3 years ago
9

Please help me with this.

Mathematics
1 answer:
inessss [21]3 years ago
8 0

Answer:

d. x = 1 1/3

Step-by-step explanation:

Step 1: Add 5/6x to both sides.

  • \frac{2}{3}x + \frac{5}{6}x = 2 - \frac{5}{6}x + \frac{5}{6}x
  • \frac{3}{2}x = 2

Step 2: Multiply both sides by 2/3.

  • \frac{3}{2}x * \frac{2}{3} = 2 * \frac{2}{3}
  • x = \frac{4}{3}
  • x = 1 \frac{1}{3}

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On its municipal website, the city of Tulsa states that the rate it charges per 5 CCF of residential water is $21.62. How do the
Daniel [21]

Answer:

hello your question is incomplete attached below is the complete question

answer :

H0 : <em> u </em>= 21.62    ( Null hypothesis )

H1 : <em> u</em> = 21.62   ( alternative hypothesis )

Step-by-step explanation:

Formulating hypothesis that can be used to determine whether the population mean rate at 5 CCF of residential water discharged by U.S public utilities differs from $21.62

H0 : <em> u </em>= 21.62    ( Null hypothesis )

H1 : <em> u</em> = 21.62   ( alternative hypothesis )

3 0
3 years ago
What are the new vertices of triangle ABC if the triangle is translated three units to the right and then three units downward?
DerKrebs [107]

Answer:

A=(0,-1), B=(5,0) and C=(-2,-6)

Step-by-step explanation:

If the translation is 3 units to the right then to every x coordinate we add three and to the y coordinate we subtract 3.

4 0
3 years ago
Which equations for the measures of the unknown
MAXImum [283]

Answer: Option B, Option C, Option E

Step-by-step explanation:

The options written correctly, are:

A)x = cos^{-1}(\frac{a}{c})\\\\B) x = sin^{-1}(\frac{c}{b})\\\\C)x = tan^{-1}(\frac{c}{a})\\\\D) y = sin^{-1}(\frac{a}{c})\\\\ E)y = cos^{-1}(\frac{c}{b})

For this exercise you need to use the following Inverse Trigonometric Functions:

1)\ sin^{-1}(x)\\\\2)\ cos^{-1}(x)\\\\3)\ tan^{-1}(x)\\\\

When  you have a Right triangle (a triangle that has an angle that measures 90 degrees) and you know that lenght of two sides, you can use the Inverse Trigonometric Functions to  find the measure of an angle \alpha:

 1)\alpha = sin^{-1}(\frac{opposite}{hypotenuse}) \\\\2)\ \alpha =cos^{-1}(\frac{adjacent}{hypotenuse})\\\\3)\ \alpha=tan^{-1}(\frac{opposite}{adjacent})

Therefore, the conclusion is that the angles "x" and "y" can be found with these equations:

x=sin^{-1}(\frac{c}{b})\\\\x= cos^{-1}(\frac{a}{b})\\\\x=tan^{-1}(\frac{c}{a})\\\\\\ y=sin^{-1}(\frac{a}{b})\\\\y=cos^{-1}(\frac{c}{b})\\\\y=tan^{-1}(\frac{a}{c})

5 0
3 years ago
Read 2 more answers
Use the given zero to find the remaining zeros of each function f(x)=2x^4+5x^3+5x^2+20x-12 zero:-2i
frutty [35]

Answer:

1/2, 3

Step-by-step explanation:

This is a pretty involved problem, so I'm going to start by laying out two facts that our going to help us get there.

  1. The Fundamental Theorem of Algebra tells us that any polynomial has <em>as many zeroes as its degree</em>. Our function f(x) has a degree of 4, so we'll have 4 zeroes. Also,
  2. Complex zeroes come in pairs. Specifically, they come in <em>conjugate pairs</em>. If -2i is a zero, 2i must be a zero, too. The "why" is beyond the scope of this response, but this result is called the "complex conjugate root theorem".

In 2., I mentioned that both -2i and 2i must be zeroes of f(x). This means that both x-2i and x+2i are factors of f(x), and furthermore, their product, x^2+4, is <em>also</em> a factor. To see what's left after we factor out that product, we can use polynomial long division to find that

2x^4+5x^3+5x^2+20x-12=(x^2+4)(2x^2+5x-3)

I'll go through to steps to factor that second expression below:

2x^2+5x-3=2x^2+6x-x-3\\=2x(x+3)-(x+3)\\=(2x-1)(x+3)

Solving both of the expressions when f(x) = 0 gets us our final two zeroes:

2x-1=0\\2x=1\\x=1/2

x+3=0\\x=-3

So, the remaining zeroes are 1/2 and 3.

8 0
4 years ago
Read 2 more answers
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